Answer:
Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m.
Explanation:
The Coulomb force between two charges,
and
, separated by a distance,
, is given

<em>k</em> is a constant.
For the charge Z to be at equilibrium, the force exerted on it by charge X must be equal and opposite to the force exerted on it by charge Y.
It is to be placed along the <em>x</em>-axis. Hence, it is on the same line as charges X and Y.
Let the charge on Z be <em>Q</em>. It is positive.
Let the distance from charge X be <em>x m.</em> Then the distance from charge Y will be (0.60 - <em>x</em>) m.
Force due to charge X

Force due to charge Y

Since both forces are equal and opposite,







Applying the quadratic formula,

or 
Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m
Magnitude of acceleration = (change of speed) / (time for the change) =
(12 m/s - 0) / (3 sec) =
12/3 = <em>4 m/s²</em>
What's a challenge question ? Have we all passed the event horizon
and been spaghettified without knowing it ?
Answer:
85 N backwards
Explanation:
u subtract then thats the net force and add direction
The SI unit for length is meters(m), for mass is kilograms(kg), for volume is cubicmeter<span>(m^3), for density kilogram per cubic </span>meter(kg<span>/m^3), for time is seconds(s), and for temperature is kelvins(K).</span>