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3 years ago

VSEPR Theory - Help soon.

Chemistry

1 answer:

Ksju [112]3 years ago

3 0

Answer:

The Valence Shell Electron Pair Repulsion Theory abbreviated as VSEPR theory is based on the premise that there is a repulsion between the pairs of valence electrons in all atoms, and the atoms will always tend to arrange themselves in a manner in which this electron pair repulsion is minimalized

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What produces the large amount of energy released by a nuclear reaction?

Bingel [31]

Fusion power is the power generated by nuclear fusion processes. In fusion reactions, two light atomic nuclei fuse together to form a heavier nucleus. In doing so, they release a comparatively large amount of energy that arises from the binding energy, creating an increase in temperature of the reactants.

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3 years ago

Iron combines with 5 g of Copper (1) Nitrate to form 6.01 g of Iron (1) Nitrate and 0.4 g of copper

Ivanshal [37]

First, you would add the products: 0.4 + 6.01 = 6.41 g
Then, to get the mass of Iron required, you would do 6.41 - 5.0 = 1.41
This is because in the conservation of mass principle it states,
mass of reactants = mass of products.

7 0

3 years ago

If kerosene has a specific gravity of 0.820, what force will be exerted on the circular bottom of a cylindrical kerosene tank th

Svet_ta [14]

Answer:

$F = 774146.534\,N$

Explanation:

The pressure at the bottom of the tank is:

$P_{bottom} = (0.820)\cdot (1000\,\frac{kg}{m^{3}})\cdot (9.807\,\frac{m}{s^{2}})\cdot (30\,ft)\cdot (\frac{0.305\,m}{1\,ft} )$

$P_{bottom} = 73581.921\,Pa$

The force exerted on the circular bottom is:

$F=(73581.921\,Pa)\cdot (\frac{\pi}{4} )\cdot [(12\,ft)\cdot (\frac{0.305\,m}{1\,ft} )]^{2}$

$F = 774146.534\,N$

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3 years ago

If you are given 608 grams of calcium phosphate Ca3(PO4)2, how many moles would you have? *

Anika [276]

Answer:

You would have 1.96 moles.

Explanation:

You are given 608 grams of calcium phosphate Ca₃(PO₄)₂.

Molar mass (M) is the amount of mass that a substance contains in one mole. This substance can be an element or a compound.

Since the molar mass of the compound Ca₃(PO₄)₂ is 310 g / mole, and taking into account the definition of molar mass, you can apply the following rule of three: if 310 grams of Ca₃(PO₄)₂ are contained in 1 mole, 608 grams of the compound in how many moles are present?

$moles=\frac{608 grams* 1 mole}{310 grams}$

moles= 1.96

<u><em>You would have 1.96 moles.</em></u>

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3 years ago

A 29.0-g sample of water at 290. K is mixed with 51.0 g water at 300. K. Calculate the final temperature of the mixture assuming

zubka84 [21]

Let me conduct my research

5 0

2 years ago

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