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Lelu [443]
3 years ago
7

Which of the following statements regarding glucose is FALSE?a) Glucose is the main component of starch and glycogen.b) Glucose

is also called blood sugar.c) Glucose is the most common disaccharide in our diet.d) Glucose is the most important carbohydrate fuel for the human body.
Chemistry
1 answer:
marishachu [46]3 years ago
8 0

Answer:

The correct option is C.

Explanation:

Carbohydrates are one of the macro molecules that are consumed by living organisms. The end product of carbohydrate is glucose. Glucose is a very important fuel that the body cells used to produce energy, which they use to carry out their daily activities. Glucose is also known as blood sugar and it is the only fuel that living cells can use for the production of ATP. Other food macro molecules such as lipids and proteins can also be converted to glucose if there is a need for that. Glucose is always stored in the body in form of glycogen.

The statement given in option C about glucose is wrong because glucose is a monosaccharide and not a disaccharide.

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Using the thermodynamic information in the ALEKS Data tab, calculate the boiling point of titanium tetrachloride . Round your an
ddd [48]

Answer:

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

TiCl_{4(l)} ⇒ TiCl_{4(g)}

ΔH°_{f} (TiCl_{4(l)}) = -804.2 kJ/mol

ΔH°_{f} (TiCl_{4(g)}) = -763.2 kJ/mol

Therefore,

ΔH°_{f} = ΔH°_{f} (TiCl_{4(g)}) - ΔH°_{f} (TiCl_{4(l)}) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(TiCl_{4(l)}) = 221.9 J/(mol*K)

s°(TiCl_{4(g)}) = 354.9 J/(mol*K)

Therefore,

s° = s° (TiCl_{4(g)}) - s°(TiCl_{4(l)}) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH°_{f} /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.

5 0
3 years ago
PLEASE HELP ME Which of the following is a Brønsted-Lowry base but not an Arrhenius base?
never [62]
Ur answer is going to be <span>NH 3 or D AND PLEASE MARK ME AS BRAINLIEST CAUSE IVE NEVER GOT BRAINLIEST BEFORE AND HAVE A GOOD DAY !</span>
4 0
2 years ago
Based on periodic properties, choose the more metallic element from each of the following pairs.
dimulka [17.4K]

Answer:

Sr is the more metallic element

Bi is the more metallic element

O is the more metallic element

As is the more metallic element

Explanation:

One thing should be clear; metallic character increases down the group but decreases across the period.

Hence, as we move across the period, elements become less metallic. As we move down the group elements become more metallic.

This is the basis upon which decisions were made about the metallic character of each of the elements listed above.

7 0
3 years ago
DIRECTIONS: Use the Word Bank to answer the questions below. For questions 2 and 3 circle the correct choice.
Angelina_Jolie [31]

Explanation:

1. Electrons surround the nucleus in defined regions called orbits.

2. The shells further away from the nucleus are ​larger​ and can hold ​more electrons.

3. The shells closer to the nucleus are ​smaller​ and can hold ​less​ electrons.

4. The closest shell (closest to the nucleus) can hold a maximum of two electrons.

5. Once the first shell is full, the second shell begins to fill. It can hold a maximum of eight electrons.

6. Once the second shell is full, the third shell begins to fill.

7. Once the third shell contains Eighteen electrons, the fourth shell begins to fill.

8. The arrangement of electrons in shells around the nucleus is referred to as an atom's electronic configuration.

8 0
3 years ago
24 grams of iron is added to a graduated
Vanyuwa [196]

Answer:

d = 8 g/mL

Explanation:

Given data:

Mass of metal = 24 g

Volume of eater = 45 mL

Volume of water + metal = 48 mL

Density of iron metal = ?

Solution:

Volume of metal:

Volume of metal = volume of water+ metal - volume of water

Volume of metal = 48 mL - 45 mL

Volume of metal = 3 mL

Density of metal:

d = m/v

d = 24 g/ 3 mL

d = 8 g/mL

4 0
2 years ago
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