Answer: 103.8 g of , 0.65 moles of
Explanation:
To calculate the moles :
Thus is the limiting reagent as it limits the formation of product and
is the excess reagent.
According to stoichiometry :
3 moles of produce = 2 moles of
Thus 0.975 moles of will produce=
of
Mass of
Thus 103.8 g of will be produced.
The molarity of the solution will be 0.72 m.
The majority of reactions take place in solutions, making it crucial to comprehend how the substance's concentration is expressed in a solution when it is present. The number of chemicals in a solution can be stated in a variety of ways, including.
The symbol for it is M, and it serves as one of the most often used concentration units. Its definition states how many moles of solute there are in a liter of solution.
Given data:
Molarity can be determined by the formula:
where, M is molarity and V is volume.
Put the value of given data in above equation.
57.3 × 0.497 m = M × 39.5 L
M = 0.72 m
Therefore, the molarity of the solution will be 0.72 m
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