Answer:
Explanation:
a )
Pressure on the bottom
= hdg
= 2.5 x 820 x 9.8
= 20090 N / m²
b )
force = area x pressure
= 20090 x 10 x 6 N
= 1205400 N
c )
Force on 10m x 2.5 m face
center of gravity of the tank will lie at height 2 .5 / 2 = 1.25 m
Pressure = hdg
= 1.25 x 820 x 9.8
= 10045 N/m²
force = pressure x area
= 10045 x 10 x 2.5
= 251125 N .
There are no rules that describe how positive energy behaves
in the presence of negative energy, because there is no such
thing as negative energy.
(Wellll ... in pop Psychology, perhaps, but not in any real science.)
Answer:
a) 39.6 m/s b) 4123 N
Explanation:
a) At the top of the loop, all of the forces point downwards (force of gravity and normal force).
Fnet=ma
ma=m(v^2/R) (centripetal acceleration)
mg=m(v^2/R)
m cancels out (this is why pilot feels weightless) so,
g=(v^2/R)
9.8 m/s^2 = v^2/160 m
v^2=1568 m^2/s^2
v=39.6 m/s
b) At the bottom of the loop, the normal force and the force of gravity point in opposite directions. The normal force is the weight felt.
Convert 300 km/hr to m/s
300 km/hr=83.3 m/s
Convert pilot's weight into mass:
760 N = 77.55 kg
Fnet=ma
n-mg=m(v^2/R)
n=(77.55 kg)(((83.3 m/s)^2)/160 m)+(77.55 kg)(9.8 m/s^2)
n=3363.2 N+760 N=4123 N
<span>One leg is = 12 m, and the other leg is 16 m. </span>
