Answer:
Basically, solubility increases with temperature. It is the case for most of the solvents. The situation is though different for gases. With increase of the temperature they became less soluble in each other and in water, but more soluble in organic solvents.
Answer:
k = 2.17E-2 s-1
Explanation:
Initial Concentration [A]o = 0.380 M
Final Concentration [A] = 0.215 M
time, t = 26.3 s
Unit of rate constant = s-1
Rate constant = ?
The units of the rate constant depends on the order of the reaction. This is a first order reaction due to the units.
The integral rate law for a first order reaction is;
ln[A] = ln[A]o - kt
ln(0.215) = ln(0.380) - k(26.3)
ln(0.215) - ln(0.380) = - k(26.3)
- k(26.3) = -0.57
k = 0.57 / 26.3 = 0.02167
Reporting to three significant figures using E notation;
k = 2.17E-2 s-1
<h2>Aspect of The Modern Model </h2>
Following is the one aspect of the modern model of the atom that agrees with a conclusion made by Thomson as following:
- Atom is a neutral particle.
- The number of electrons and protons are always equal in an atom according to their atomic number.
- Atomic number is the number of protons in an atom.
Answer:
Options (A), (B) and (C)
Explanation:
In an ecosystem, the transfer of nutrients takes place from one place o another. This input and output of nutrients continuously takes place in the ecosystem.
- The rainwater is also essential as it carries a certain amount of valuable nutrients such as calcium, fluoride, magnesium, and iron that are mixed with water, and this enriches the fertility of the soil and the water is taken up by the roots of the plants for the growth and expansion of plants.
- The nitrogen-fixing bacteria refers to those micro-organisms that are present in the soil and helps in the conversion of the atmospheric nitrogen into nitrogen compounds, which are helpful for the enhancement of the soil fertility.
- Chemical weathering usually refers to the process by which the rocks disintegrates due to the effect of chemical reactions. The micro-organisms and the plant roots release some acids sometimes that react with the rocks and help in breakdown releasing the nutrients that are stored in the rocks. This eventually mixes up with the soil and increases the quality of the soil.
Thus, the correct answers are options (A), (B) and (C).
Answer:
![C_2H_6O](https://tex.z-dn.net/?f=C_2H_6O)
Explanation:
The first step is the <u>calculation of the moles</u> of
and
, so:
![114.6~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=2.6~mol~of~CO_2](https://tex.z-dn.net/?f=114.6~g~CO_2%5Cfrac%7B1~mol~CO_2%7D%7B44~g~CO_2%7D%3D2.6~mol~of~CO_2)
![70.44~g~H_2O\frac{1~mol~H_2O}{18~g~H_2O}=~3.9~mol~H_2O](https://tex.z-dn.net/?f=70.44~g~H_2O%5Cfrac%7B1~mol~H_2O%7D%7B18~g~H_2O%7D%3D~3.9~mol~H_2O)
Now, in 1 mol of CO2 we have 1 mol of C and in 1 mol of
we have 1 mol of H. Additionally, if we want to calculate the moles of oxygen we need to <u>calculate the grams of C and O</u> and then do the <u>substraction</u> form the initial amount, so:
![Total~grams=~31.25~+~7.82=39.08~g](https://tex.z-dn.net/?f=Total~grams%3D~31.25~%2B~7.82%3D39.08~g)
![grams~of~O=60.00~g-~39.08~g=20.92~g~of~O](https://tex.z-dn.net/?f=grams~of~O%3D60.00~g-~39.08~g%3D20.92~g~of~O)
Now we can <u>convert the grams</u> of O to moles, so:
![20.92~g~of~O\frac{1~mol~O}{16~g~O}=1.30~mol~O](https://tex.z-dn.net/?f=20.92~g~of~O%5Cfrac%7B1~mol~O%7D%7B16~g~O%7D%3D1.30~mol~O)
The next step is to divide all the mol values by the <u>smallest one</u>:
![O=\frac{1.30~mol~O}{1.30~mol~O}=~1](https://tex.z-dn.net/?f=O%3D%5Cfrac%7B1.30~mol~O%7D%7B1.30~mol~O%7D%3D~1)
![C=\frac{2.6~mol~C}{1.30~mol~O}=~2](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B2.6~mol~C%7D%7B1.30~mol~O%7D%3D~2)
![H=\frac{7.82~mol~H}{1.30~mol~O}=6](https://tex.z-dn.net/?f=H%3D%5Cfrac%7B7.82~mol~H%7D%7B1.30~mol~O%7D%3D6)
Therefore the formula is ![C_2H_6O](https://tex.z-dn.net/?f=C_2H_6O)