The mixture contains 62 % one isomer and 38 % the enantiomer.
Let’s say that the mixture contains 62 % of the (<em>R</em>)-isomer.
Then % (<em>S</em>) = 100 % -62 % = 38 %
ee = % (<em>R</em>) - % (<em>S</em>) = 62 % -38 % = 24 %
The elements Carbon, Hydrogen, and Oxygen are all part of Non-Metals.
Hope This Helps! :)
Answer:
BCI3 is a non polar compound because there is no neutral in it
