1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nikitich [7]
3 years ago
6

BRAINLIESTTT ASAP!!! PLEASE ANSWER!

Chemistry
2 answers:
zmey [24]3 years ago
7 0

Physical characteristics include change in shape, size, texture, color, smell, density, boiling/melting point, solubility, etc., so any change with those properties would be proof of a physical reaction.

sladkih [1.3K]3 years ago
4 0

If the item or substance has changed into a state where you are able to change it back such as:

Water melting

Water freezing

You might be interested in
Balance the following equation:<br>sodium + Sodium Nitrate = Sodium Oxide + Nitrogen
-Dominant- [34]
Na + NaNO3 = Na2O + N2

4 Na + 2 NaNO3 = 6 Na2O + N2

6 Na on each side
2 N on each side
6 O on each side
6 0
3 years ago
The chemical properties of an atom are related to the arrangement of what
jolli1 [7]
Chemical properties of an atom are based upon the arrangement of valence electrons (electrons which can be gained, lost, or shared).
4 0
3 years ago
Consider a solution containing .100 M fluoride ions and .126M hydrogen fluoride. The concentration of fluoride ions after the ad
S_A_V [24]
Given:

Concentration of Fluoride ions = 0.100 M
Concentration of Hydrogen Fluoride = 0.126 M

Asked: Concentration of fluoride ions after the addition of 5ml of 0.0100 M HCl to 25 mL of the solution

Assume: 50:50 ratio of fluoride ions and HF

12.5ml*0.1mol/L *1L/1000mL + 12.5*0.126mol/L * 1L/1000mL = 2.825x10^-3 moles F-

5ml * 0.01 mol/L *1L/1000mL = 5x10^-5 moles

Assume: Volume additive

Final concentration = 2.825x10^-3 + 5x10^-5 moles/ 30 ml * 1000ml/L =0.0958 M
<span />
3 0
3 years ago
A solution contains 0.60 mg/ml mn2+. what minimum mass of kio4 must me added to 5.00 ml of the solution in order to completely o
azamat
The given solution of Mn²⁺ is 0.60 mg/mL.
Hence mass of Mn²⁺ in 5 mL of solution = 0.60 mg/mL x 5 mL = 3 mg

Molar mass of Mn = 54.9 g/mol
Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol

The balanced equation for the reaction is,
2Mn²⁺ + 5KIO₄ + 3H₂O → 2MnO₄⁻ + 5KIO₃ + 6H⁺

The stoichiometric ratio between Mn²⁺ and KIO₄ is 2 : 5

Hence, moles of KIO₄ reacted = 5.46 x 10⁻⁵ mol x (5 / 2)
                                                 = 13.65 x 10⁻⁵ mol
Molar mass of KIO₄ = 230 g/mol

Hence needed mass of KIO₄ = 13.65 x 10⁻⁵ mol x 230 g/mol
                                               = 0.031395 g
                                               = 31.395 mg
                                               ≈ 31.4 mg
5 0
3 years ago
The amount of water that evaporates from earth is
astraxan [27]
<span>Evaporation from the oceans is the primary mechanism supporting the surface-to-atmosphere portion of the water cycle</span>
3 0
4 years ago
Read 2 more answers
Other questions:
  • The volume of the nucleus of a carbon atom is about 9.9 10⁻³⁹. the molar mass of carbon is 12.00 g mol⁻¹. what is the density of
    11·1 answer
  • I need heLp ASAP
    7·2 answers
  • This reaction is an explosive reaction of a strong acid combining with a strong base.
    7·2 answers
  • A balanced chemical equation must account for every atom involved in a chemical reaction.
    9·1 answer
  • Two containers, one with a volume of 3.0 L and the other with a volume of 2.0 L contain, respectively, argon gas at 1.1 atm and
    14·1 answer
  • What is the mass of oxygen gas in a 16.8 l container at 23.0◦c and 2.50 atm? answer in units of g?
    9·1 answer
  • In science, all ideas are not tested with evidence from the natural world.
    5·2 answers
  • What type of reaction is Cl2+2NaBr=NaCl+Br2
    11·1 answer
  • Is it A? <br> NEED HELP ASAP PLEASE
    11·2 answers
  • Write down the procedure for the test of presence of nitrogen in organic compound
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!