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3 years ago

Hey i am quite confused on this question, if someone could help me understand it i would really appreciate! :)

Physics

2 answers:

Alekssandra [29.7K]3 years ago

8 0

You have to create table using cubic meters and the unit Kelvin to measure the temperature.

yarga [219]3 years ago

7 0

I did an experiment. Experiment was to strech tungsten until it fractured. My "tensometer" had a manual graph plotter. So I was able to plot the force vs extension of the tungsten.

When it broke, there was a loud bang. And it was hot to touch.

qualitative abive.

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quantitaive data could have been had I measured ad recorded the temperature of

the tungsten, and recorded the force and extension in a table of values.

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1hp is written in electric motor what does it mean

Angelina_Jolie [31]

Explanation:

The horsepower (hp) is a unit in the foot-pound-second ( fps ) or English system, sometimes used to express the rate at which mechanical energy is expended. It was originally defined as 550 foot-pounds per second (ft-lb/s). A power level of 1 hp is approximately equivalent to 746 watt s (W) or 0.746 kilowatt s (kW).

5 0

3 years ago

A spotlight on a boat is y = 2.2 m above the water, and the light strikes the water at a point that is x = 8.5 m horizontally di

slava [35]

Answer:

The answer to the question is

The distance d, which locates the point where the light strikes the bottom is 29.345 m from the spotlight.

Explanation:

To solve the question we note that Snell's law states that

The product of the incident index and the sine of the angle of incident is equal to the product of the refractive index and the sine of the angle of refraction

n₁sinθ₁ = n₂sinθ₂

y = 2.2 m and strikes at x = 8.5 m, therefore tanθ₁ = 2.2/8.5 = 0.259 and

θ₁ = 14.511 °

n₁ = 1.0003 = refractive index of air

n₂ = 1.33 = refractive index of water

Therefore sinθ₂ = $\frac{n_1sin\theta_1}{n_2}$ = $\frac{1.003*0.251}{1.33}$ = 0.1885 and θ₂ = 10.86 °

Since the water depth is 4.0 m we have tanθ₂ = $\frac{4}{x_2}$ or x₂ = $\frac{4}{tan\theta_2 }$ = $\frac{4}{tan(10.86)}$ = 20.845 m

d = x₂ + 8.5 = 20.845 m + 8.5 m = 29.345 m.

5 0

3 years ago

Crystallization is a separation technique used to produce rock candy from a sugar solution. true or false

Zinaida [17]

This is true due to the reaction that happens from water evaporating and leaving the sugar crystals behind to form.

3 0

3 years ago

A horizontal 745 N merry-go-round of radius

Arturiano [62]

Answer:

The kinetic energy of the merry-goround after 3.62 s is 544J

Explanation:

Given :

Weight w = 745 N

Radius r = 1.45 m

Force = 56.3 N

To Find:

The kinetic energy of the merry-go round after 3.62 = ?

Solution:

Step 1: Finding the Mass of merry-go-round

$m = \frac{ weight}{g}$

$m = \frac{745}{9.81 }$

m = 76.02 kg

Step 2: Finding the Moment of Inertia of solid cylinder

Moment of Inertia of solid cylinder I = $0.5 \times m \times r^2$

Substituting the values

Moment of Inertia of solid cylinder I

=> $0.5 \times 76.02 \times (1.45)^2$

=> $0.5 \times 76.02\times 2.1025$

=> $79.91 kg.m^2$

Step 3: Finding the Torque applied T

Torque applied T = $F \times r$

Substituting the values

T = $56.3 \times 1.45$

T = 81.635 N.m

Step 4: Finding the Angular acceleration

Angular acceleration , $\alpha = \frac{Torque}{Inertia}$

Substituting the values,

$\alpha = \frac{81.635}{79.91}$

$\alpha = 1.021 rad/s^2$

Step 4: Finding the Final angular velocity

Final angular velocity , $\omega = \alpha \times t$

Substituting the values,

$\omega = 1.021 \times 3.62$

$\omega = 3.69 rad/s$

Now KE (100% rotational) after 3.62s is:

KE = $0.5 \times I \times \omega^2$

KE = $0.5 \times 79.91 \times 3.69^2$

KE = 544J

6 0

3 years ago

Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another and ends up as what?

barxatty [35]

Answer:

Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.

Explanation:

The solar energy cycle functions in the following form:

Considering that 100% of energy is directed at earth.
When 100% light is incident on the Earth's surface about 6-7% of it is reflected back by the atmosphere into space.
20% is reflected back by the clouds.
And about 4% is reflected back by Earth's surface.
16% of solar energy is absorbed by the atmosphere, 3% is absorbed by clouds and 51% is absorbed by land and ocean.
From the absorbed energy, 64% is radiated back to space from clouds and atmosphere and 6% is directly radiated back to space from earth.
From the radiated energy 15% is absorbed by the atmosphere and 23% is carried by the clouds and atmosphere through the latent heat in water vapor.

Therefore, absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.

Learn more about solar energy here:

<u>brainly.com/question/18175736</u>

#SPJ4

6 0

2 years ago