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svet-max [94.6K]
3 years ago
11

For the given network:

Engineering
1 answer:
Jet001 [13]3 years ago
7 0

Answer:

0.5274 lagging.

Explanation:

So, we are given the following data or parameters or information which is what we need in order to solve this kind of question effectively. So, we have;

=> " For the given network:

ZR = 100 [Ω] , ZL = j124 [Ω], and ZC = - j89 [Ω]"

And we are asked to find the power factor. The power factor can be found or determined or calculated as;

7eq= 100 + j ( 24) (-89).

7eq = 124 × 89 - j89 × 100/ 100 + j35

7 eq= 133.81 L- 58.17.

Thus, the power factor is equal to;

=> Cos (58.17)= 0.5274 lagging.

Hence, the correct answer to this question is 0.5274 lagging.

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A cylinder with a piston restrained by a linear spring contains 2 kg of carbon dioxide at 500 kPa and 400°C. It is cooled to 40°
leonid [27]

Answer:

heat transfer for the process is - 643.3 kJ

Explanation:

given data

mass m = 2 kg

pressure p1 = 500 kPa

temperature t1 = 400°C = 673.15 K

temperature t2 = 40°C = 313.15 K

pressure p2 = 300 kPa

to find out

heat transfer for the process

solution

we know here mass is constant so

m1 = m2

so by energy equation

m ( u2 - u1 ) = Q - W

Q is heat transfer

and in process  P =  A+ N that is linear spring

so

W = ∫PdV

= 0.5 ( P1+P2) ( V1 - V2)

so for case 1

P1V1 = mRT

put here value

500 V1 = 2 (0.18892) (673.15)

V1 = 0.5087 m³

and

for case 2

P2V2 = nRT

300 V2 = 2 (0.18892) (313.15)

V2 = 0.3944 m³

and

here W will be

W = 0.5 ( 500 + 300 ) ( 0.3944 - 0.5087 )

W = -45.72 kJ

and

Q is here for Cv = 0.83 from ideal gas table

Q = mCv ( T2-T1 ) + W

Q = 2 × 0.83 ( 40 - 400 ) - 45.72

Q = - 643.3 kJ

heat transfer for the process is - 643.3 kJ

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4 years ago
1. Springs____________<br> energy when compressed<br> And _________energy when they rebound.
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Answer:

Springs store energy when compressed and release energy when they rebound

Explanation:

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