Answer:
- Light is bounced back at same angle (Classical Reflection)
- Light penetrates medium at different angle due to different material densities (Refraction)
Light bounces at different angles in periodic grid (Reflected Diffraction)
Light enters medium at different angles through a grid (Transmission Diffraction)
- Light EMF field looses one axis component (Polarized filter)
Explanation:
Reflection is a phenomenon in which waves (light included) bounce back from an obstacle at the same angle of incidence
Refraction is the change in the angle of a wave as it enters the interface of two media. The change in angle is due to the difference in the densities of the two media.
Reflected diffraction occurs when an optical component with a periodic grid, splits, and diffracts light into several beams travelling in different directions. The light light bounces at an angle in the periodic grid.
Transmission diffraction is dispersion a beam of various wavelengths into a spectrum of associated lines due to the principle of diffraction. In this type of diffraction, light enters medium at different angles through a grid.
Polarized filters removes one field from the incidence electromagnetic wave like light, leaving it to vibrate in only one plane.
When the handler has reached the point of balance of the animal, they should stop walking so that they may move only one animal at a time. The point of balance for cattle that are being worked with in limited places such as races and chutes is often found at the animal's shoulder, as seen by the diagrams.
This is further explained below.
<h3>What is a chute?</h3>
Generally, Chutes are channels, planes, or passageways that are either vertical or slanted and through which things may be transported using only gravity.
In conclusion, When the handler has reached the point where the animal's point of balance has been crossed, they should stop walking so that they may move just one animal.
As seen in the illustrations, the point of balance for cattle being worked with in restricted spaces like races and chutes is often located at the animal's shoulder.
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Answer:
Tension in cable BE= 196.2 N
Reactions A and D both are 73.575 N
Explanation:
The free body diagram is as attached sketch. At equilibrium, sum of forces along y axis will be 0 hence
hence
Therefore, tension in the cable, 
Taking moments about point A, with clockwise moments as positive while anticlockwise moments as negative then
Similarly,
Therefore, both reactions at A and D are 73.575 N
Answer:
The minimum particle diameter that is removed at 85% is 1.474 * 10 ^⁻4 meters.
Solution
Given:
Length = 48 m
Width = 12 m
Depth = 3m
Flow rate = 4 m 3 /s
Water density = 10 3 kg/m 3
Dynamic viscosity = 1.30710 -3 N.sec/m
Now,
At the minimum particular diameter it is stated as follows:
The Reynolds number= 0.1
Thus,
0.1 =ρVTD/μ
VT = Dp² ( ρp- ρ) g/ 10μ²
Where
gn = The case/issue of sedimentation
VT = Terminal velocity
So,
0.1 = Dp³ ( ρp- ρ) g/ 10μ²
This becomes,
0.1 = 1000 * dp³ (1100-1000) g 0.1/ 10 *(1.307 * 10 ^⁻3)²
= 3.074 * 10 ^⁻6 = dp³ (.g01 * 10^6)
dp³=3.1343 * 10 ^⁻12
Dp minimum= 1.474 * 10 ^⁻4 meters.
Answer:
Logarithmic decrement is equal to 0.182
Explanation:
given,
amplitude decay = 9 dB
number of cycles = 12 cycles
mass of the system = 7 kg
spring stiffness = 3000 N/m
logarithmic decrement = ?
now,
logarithmic decreament = 
= 
=ln (1.2)
= 0.182
Hence, Logarithmic decrement is equal to 0.182
