Answer:
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Writing an Essay on Engineering as Required by Your Instructor
Determine the audience and purpose of essay writing;
Decide on an essay topic;
Research some reliable sources of information;
Develop the main arguments and supporting points;
Start writing an essay according to the basic structure;
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Answer:
irreversible head loss is 38.51 ft
mechanical power 6.55 hp
Explanation:
Given data:
Pump Power 12 hp = 8948.39 watt = 6600 lbs ft/sec
Q = 1.5 ft^3/s
Pump actually delivers 
Power that water gains
hence Power lost = 6600 - 2995.2 3604.8 lbs ft/sec = 6.55 hp
head loss
hl = 38.51 ft
Answer: 0.053
Explanation:
So, we convert 5.3 grams into kilograms.
5.3g = 0.0053 kg (Since 1kg equals 1000g)
On Earth, gravity is 10 N/kg.
Weight = mass x gravity
Weight = 0.0053kg x 10 N/kg
Weight = 0.053 Newtons (On Earth)
This is true. Anything the government does has a positive or negative effect on anything including businesses.
Answer:
Enthalpy, hsteam = 2663.7 kJ/kg
Volume, Vsteam = 0.3598613 m^3 / kg
Density = 2.67 kg/ m^3
Explanation:
Mass of steam, m = 1 kg
Pressure of the steam, P = 0.5 MN/m^2
Dryness fraction, x = 0.96
At P = 0.5 MPa:
Tsat = 151.831°C
Vf = 0.00109255 m^3 / kg
Vg = 0.37481 m^3 / kg
hf = 640.09 kJ/kg
hg = 2748.1 kJ/kg
hfg = 2108 kJ/kg
The enthalpy can be given by the formula:
hsteam = hf + x * hfg
hsteam = 640.09 + ( 0.96 * 2108)
hsteam = 2663.7 kJ/kg
The volume of the steam can be given as:
Vsteam = Vf + x(Vg - Vf)
Vsteam = 0.00109255 + 0.96(0.37481 - 640.09)
Vsteam = 0.3598613 m^3 / kg
From the steam table, the density of the steam at a pressure of 0.5 MPa is 2.67 kg/ m^3
