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3 years ago

In order for an object to have kinetic energy it must have a mass and a ?

Physics

1 answer:

almond37 [142]3 years ago

8 0

Answer:

Velocity

Explanation:

The mechanical energy of the body is defined as the sum of the potential energy and kinetic energy.

E = P.E + K.E

The potential energy of a body is due to the height from the surface of the earth.

P.E = mgh

The kinetic energy of the is possessed by the body due to the virtue of its motion,

K.E = ½ mv²

If there is no velocity associated with the body, there is no K.E in the body.

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A 1400 kg car is moving at 12 m/s when the driver stops a car what increase in the thermal energy of the car and it surroundings

butalik [34]

KE = 1/2 mv^2

in this case, the initial kinetic energy which is converted to heat is

KE = 1/2 1400 (12)^2

KE = 100,800 J

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3 years ago

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A force of 500 N acts horizontally on a 10,000 g body. What is its horizontal acceleration

Paladinen [302]

200n because it's 2×5=10so maybe try solving the problem like that ok does that help

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3 years ago

(a) A light-rail commuter train accelerates at a rate of 1.35 m/s2 . How long does it take to reach its top speed of 80.0 km/h,

Mashcka [7]

Answer:

(a) Time t = 16.46 sec

(b) Time t =13.466 sec

Explanation:

(a) As the train starts from rest its initial velocity u = 0 m/sec

Acceleration $a=1.35m/sec^2$

Final speed v = 80 km/hr

$80km/hr=\frac{80\times 1000}{3600sec}=22.22m/sec$

From first equation of motion v =u+at

So $t=\frac{v-u}{a}=\frac{22.22-0}{1.35}=16.46 sec$

(b) Now initial speed u = 22.22 m/sec

As finally train comes to rest so final speed v=0 m/sec

Deceleration $a=1.65m/sec^2$

So $t=\frac{v-u}{a}=\frac{0-22.22}{-1.65}=13.466 sec$

Final velocity v = 0 m/sec

Time t = 8.30 sec

So acceleration is given by

$a=\frac{v-u}{t}=\frac{0-22.22}{8.3}=-2.6771m/sec^2$

As acceleration is negative so it is a deceleration

7 0

3 years ago

A cook preparing a meal for a group of people is an example of

Fudgin [204]

Kinetic and potential energy he has the ability to make a meal and because he is making the meal

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3 years ago

A horizontal uniform meter stick supported at the 50-cm mark has a mass of 0.50 kg hanging from it at the 20-cm mark and a 0.30

ElenaW [278]

Answer:

70 cm

Explanation:

0.5 kg at 20 cm

0.3 kg at 60 cm

x = Distance of the third 0.6 kg mass

Meter stick hanging at 50 cm

Torque about the support point is given by (torque is conserved)

$0.5(50-20)=0.3(60-50)+0.6x\\\Rightarrow x=\dfrac{0.5(50-20)-0.3(60-50)}{0.6}\\\Rightarrow x=20\ cm$

The position of the third mass of 0.6 kg is at 20+50 = 70 cm

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3 years ago

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