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Cloud [144]
3 years ago
11

What is the name of the North Star?

Physics
1 answer:
meriva3 years ago
5 0
<span>Polaris might be the answer you are looking for</span>
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The record for the highest speed achieved in alaboratory for a
Ira Lisetskai [31]

Answer:

0.000234 seconds

Explanation:

Since the row is 0.15m, its radius of rotation must be 0.15 / 2 = 0.075 m

We can start by calculating the angular speed of the rod:

\omega = \frac{v}{r} = \frac{2010}{0.075} = 26800 rad/s

Since one revolution equals to 2π rad. The speed in revolution per second must be

26800 / 2π = 4265 revolution/s

The number of seconds per revolution, or period, is the inverse:

1/4265 = 0.000234 seconds

3 0
3 years ago
If you wanted to increase the gravitational force between two objects what would you do
adelina 88 [10]
Double the force on the object
6 0
4 years ago
Read 2 more answers
In photosynthesis, carbon dioxide is converted to oxygen and then released.
3241004551 [841]
What is the question yes it is converted to and then released
7 0
3 years ago
Read 2 more answers
A student carries a very heavy backpack. To lift the backpack off the ground, the student must apply 80 N of force to do so. The
Xelga [282]

The work done on the backpack by the student applies 80 N of force to lift the backpack 1.5 m is 120J.

<h3>How to calculate work done?</h3>

Work done is a measure of energy expended in moving an object; most commonly, force times distance.

It is said that no work is done if the object does not move, hence, the work done on an object can be calculated as follows:

Work done = Force × Distance

According to this question, a student carries a very heavy backpack and to lift the backpack off the ground, the student must apply 80 N of force to lift the backpack 1.5 m.

Work done = 80N × 1.5m

Work done = 120J

Therefore, the work done on the backpack by the student applies 80 N of force to lift the backpack 1.5 m is 120J.

Learn more about work done at: brainly.com/question/28172139

#SPJ1

8 0
2 years ago
A system of inertia 0.47 kg consists of a spring gun attached to a cart and a projectile. The system is at rest on a horizontal
Vlad [161]

Answer:

v'=0.83m/a and v=10.2m/s

Explanation:

The information that we have is:

m_1=0.050kg\\m_2=0.47kg\\\theta = 40\\h=2.2m

The maximum height of the projectile is given by the equation

h=\frac{v^2sin^2\theta}{2g}

So, rearrange for the velocity,

v=\sqrt{\frac{2gh}{sin^2\theta}}\\v=\sqrt{\frac{2*9.8*2.2}{sin^2(40)}}\\v=10.2m/s

Apply the conservation of momentum,

mvcos(\theta)=m'v'

Then rearrange the recoil speed,

v'=\frac{mvcos\theta}{m_2}\\v'=\frac{0.05*10.2*cos40}{0.47}\\v'=0.83m/s\\

4 0
3 years ago
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