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3 years ago

A 2.00-kg object traveling east at 20.0 m/s collides with a 3.00-kg object traveling west at 10.0 m/s.

2 answers:

8 0

Momentum = mass x velocity

Before collision
Momentum 1 = 2 kg x 20 m /s = 40 kg x m/s
Momentum 2 = 3 kg x -10m/s = -30 kg x m/s

After collision
Momentum 1 = 2 kg x -5 m/s = -10 m/s
Momentum 2 = 3 kg x V2 = 3V2

Total momentum before = total momentum after
40 + -30 = -10 + 3V2
V2 = <span>6.67 m/s

Total kinetic energy before
</span><span>= (1/2) [ 2 kg * 20 m/s * 2 + 3 kg * ( -10 m/s) *2 ]
= 550 J
</span>
<span>Total kinetic energy after
</span>= (1/2) [ 2 kg * ( - 5 m/s) * 2 + 3 kg * 6.67 m/s *2 ]
= 91.73 J

Total kinetic energy lost during collision
=<span>550 J - 91.73 J
= 458.27 J</span>

Stells [14]3 years ago

4 0

Kinetic energy before:

E = 0.5mv^2 + 0.5mv^2

= 0.5*2*20^2 + 0.5*3*(-10)^2

= 400 + 150

= 550J

Kinetic energy after:

E = 0.5mv^2

= 0.5*2*(-5)^2

= 25J

Kinetic energy lost during the collision:

E = 550 - 25

= 525J

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Tracy makes a list of energy transformations that occur as an engine runs to power a car. 1. chemical energy transforms into the

alex41 [277]

Transformation 3 should Tracy removed from the list. Chemical energy transforms into gravitational potential energy.

<h3> What is the law of conservation of energy?</h3>

According to the Law of Conservation of Energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.

The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.

Transformations that occur as an engine runs to power a car is;

1. Chemical energy of fuel transforms into thermal energy.

2. Thermal energy transforms into electrical energy used to lighten the bulb in a car.

3. Thermal energy transforms into kinetic energy to help to run the car.

Chemical energy transforms into gravitational potential energy is the incorrect energy transformation.

Hence, transformation 3 should Tracy removed from the list.

To learn more about the law of conservation of energy, refer to brainly.com/question/2137260.

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8 0

2 years ago

In a mass spectrometer, a single-charged particle (charge e) has a speed of 1.0 × 10 6 m/s and enters a uniform magnetic field o

Nonamiya [84]

Answer:

The mass is $m =6.4*10^{-28} \ kg$

Explanation:

From the question we are told that

The speed of the charge is $v = 1.0 *10^{6} \ m/s$

The magnetic field is $B = 0.20 \ T$

The radius is $r = 0.02 \ m$

The value of the charge is $e = 1.60 *10^{-19} \ C$

The centripetal acting on the charge moving in the circular orbit is mathematically represented as

$F_c = \frac{mv^2}{r }$

Now this centripetal force is due to the force exerted on the charge by the magnetic field on the charge which is mathematically represented as

$F_m = qv B sin\theta$

At the maximum of this magnetic force $\theta = 90 ^o$

$F_m = e v B sin(90)$

$F_m = e v B$

Now given that it is this magnetic force that is causing the circular motion we have that

$F_c = F_m$

=> $\frac{mv^2}{r } = ev B$

=> $m = \frac{e * B * r }{v }$

substituting values

$m = \frac{ 1.60 *10^{-19} * 0.20 * 0.020 }{1.0*10^{6} }$

$m =6.4*10^{-28} \ kg$

8 0

4 years ago

A force of 400-N pushes on a 25-kg box horizontally. The box accelerates at 9 m/s? Find the coefficient of kinetic friction betw

umka2103 [35]

Answer:

Explanation:

Using the Newtons law of motion;

$\sum Fx = ma_x\\Fm - Ff = ma_x$

Fm is the moving force = 400N

Ff is the frictional force = μR

μ is the coefficient of kinetic friction

R is the reaction = mg

m is the mass

a is the acceleration

The equation becomes;

$Fm - \mu R = ma_x\\Fm - \mu mg = ma_x\\400- \mu (25)(9.8) = 25(9)\\400 - 254.8 \mu = 225\\- 254.8 \mu = 225 - 400\\- 254.8 \mu = -175\\ \mu = \frac{-175}{- 254.8} \\\mu = 0.69$