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galben [10]
3 years ago
13

A race car makes one lap around a track of radius 50 m in 9.0 s. What is the average velocity? *

Physics
1 answer:
frez [133]3 years ago
8 0

With velocity, you have to be careful.  With velocity, it doesn't matter how much total distance you covered while you were moving.  All that matters is the straight-line distance between the place you started from and the place where you stopped.  

If you ended in the same place where you started from, then it doesn't matter whether you drove around town all day and then came home, or ran around laps on a circular track, or zig-zagged back and forth a hundred times.  The straight distance from your start-point to your end-point is zero.  So technically, according to the defintion of velocity, it was <em>ZERO</em>.  

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As Aubrey watches this merry-go-round for a total of 2 minutes, she notices the black horse pass by 15 times. What is the period
marishachu [46]
2 min = 120 sec

120/15 = 8

The black horse represents 8 seconds.
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3 years ago
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The weight of a girl with a mass of 40.0 kg is_N
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Explanation:

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2 years ago
The valve in the exit pipe is closed . The density of water is 1000kg / m and the gravitational force on free fall of water is 1
Stels [109]

Answer:

300000

Explanation:

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A spring with constant k = 78 N/m is at the base of a frictionless, 30.0°-inclined plane. A 0.50-kg block is pressed against the
olasank [31]

Explanation:

The given data is as follows.

   Spring constant (k) = 78 N/m,     \theta = 30^{o}

 Mass of block (m) = 0.50 kg

According to the formula of energy conservation,

                mgh sin \theta = \frac{1}{2}kx^{2}

       h = \frac{1}{2} \times \frac{kx^{2}}{mg Sin \theta}

          = \frac{78 \times 0.04}{2 \times 0.5 \times 9.8 \times 0.5}

          = 0.64 m

Thus, we can conclude that the distance traveled by the block is 0.64 m.

4 0
3 years ago
A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a
GuDViN [60]

Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

Explanation:

From Newton's second law, F = mg and also from coulomb's law F= Eq

Dividing both equations by mass;

F/m = Eq/m = mg/m, then

g = Eq/m --------equation 1

Again, in a projectile motion, the time of flight (T) is given as

T = (2usinθ/g) ---------equation 2

Substitute in the value of g into equation 2

T = \frac{2usin \theta}{\frac{Eq}{m}} =\frac{m* 2usin \theta}{Eq}

Charge of proton = 1.6 X 10⁻¹⁹ C

Mass of proton = 1.67 X 10⁻²⁷ kg

E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°

Solving for T;

T = \frac{(1.67X10^{-27}* 2*3X10^4sin 30}{400*1.6X10^{-19}}

T = 7.83 X10⁻⁷ s

6 0
3 years ago
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