L = r x p = rmv = mr²ω
L = 0.25 x 0.75² x 12.5 = 1.758
We can apply Ampere's law to find the magnetic field generated by a loop of wire: taking any closed loop, the line integral of the magnetic field on this loop is equal to the product between the permeability

times the current flowing through this loop.
In our example, let's take a rectangular path with one side of length L parallel to to the axis of the wire loop. The contribution on the two other perpendicular sides is zero, as well as for the side outside the wire loop, so the only relevant contribution of the magnetic field is BL. So we have

where I is the current flowing through the wire loop, and N the number of loops in the length L. So we can write the magnetic field inside the wire loop as

where

is the number of loops per unit of length.
Using the right hand rule, one can see that the field inside the wire loop has the same direction of the axis of the wire loop, while the contribution outside the wire loop is negligible.
Answer: The De broglie's wavelength is 1.45×10^-14m
Explanation:
Using De broglie's equation
λ= h/mv
Where h= Planck's constant = 6.6×10^-34Js
m= mass in kilogram = 3.8×10^-28kg
V= velocity = acceleration ×time =
2.4×10^7 ×5
V= 1.2×10^8m/s
λ= is the De broglie's wavelength
λ= 6.6×10^-34Js /(3.8×10^-28kg ×1.2×10^8)
λ= 1.45×10^-14m
Therefore ,De broglie's wavelength=
1.45×10^-14m
Don't need the mass (23), but only the atomic number (11). The ion has 1 electron stripped, 10 remaining.
The rocket will cover
distance in 4. 5 s. Acceleration can be defined as the change in velocity.
<h3>
What is acceleration?</h3>
Acceleration can be defined as the change in speed or the direction of the object.
From kinamatic equation:

Where,
- final velocity = 445 m/s
- initial valocity = 0 m/s
- acceleration = 99. 0 m/s²
- time = 4. 50 s
Put the values in the formula,

Therefore, the rocket will cover
distance in 4. 5 s.
Learn more about Acceleration :
brainly.com/question/2697545