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svp [43]
3 years ago
10

PLEASE ANSWER FIRST GETS BRAINLIEST

Physics
2 answers:
Ghella [55]3 years ago
8 0

Answer:

I think it's d. The coil gains an electical current

Explanation:

lesantik [10]3 years ago
4 0
Probably D...well, i think
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What is another example of convection
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Radiator. A radiator puts warm air out at the top and draws in cooler air at the bottom. steaming cup of hot tea - The steam you see when drinking a cup of hot tea indicates that heat is being transferred into the air. ice melting/Ice melts because heat moves to the ice from the air
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3 years ago
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A SI unit used to measure force, equal to less than one-quarter of a pound, is the what
bulgar [2K]

The SI unit of force is the Newton.

1 newton is the force that accelerates a 1 kilogram mass
at the rate of 1 meter per second².

1 pound of force is equivalent to roughly  4.448 newtons.

(1 newton is equivalent to roughly  0.225  pounds of force.)

4 0
3 years ago
Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial spe
iris [78.8K]

Answer:

Explanation:

1.  V_{x} = V_{0} * cos\alpha ⇒ 16*cos32 ≈ 13.6 m/s (13.56)

2. V_{y} = V_{0} * sin\alpha ⇒ 16* sin32 ≈ 9.4 m/s

3. y_{max} = \frac{v_{0}^2*sin^2\alpha}{2g}= \frac{16^2*sin^232}{2*9.8} (the g (gravity) depends on the country but i'll take the average g which is 9.2m/s^2)

y_{max} ≈ 3.6677+1.5 ≈ 5.2m

4.  x_{max} = \frac{v_{0}^2*sin(2\alpha)}{g}=\frac{16^2*sin(2*32)}{9.8} ≈ 23.5m (23.47)

5. -

answer 4 could be wrong, not certain about that one and i don't know 5

3 0
3 years ago
HELP PLS WHAT IS Y COMPONENT
jeka94

Answer:

11.5

Explanation:

you do 12(sin 73.3) because its on the y you do sin

6 0
3 years ago
Problem 02.061 For the given circuit, assume vS = 10 V, R1 = 9 Ω, R2 = 4 Ω, R3 = 4 Ω, R4 = 5 Ω, and R5 = 4 Ω. Reference Book &am
stich3 [128]

Answer:

Ws=8.75 Watts

Explanation:

As per fig. of prob 02.061, it is clear that R5 and R4 are in parallel, its equivalent Resistance will be:

\frac{1}{Req45}=\frac{1}{R4}+\frac{1}{R5}

\frac{1}{Req45}=\frac{1}{5}+\frac{1}{4}

\frac{1}{Req45}=0.2+0.25=0.45\\ Req45=2.22

Now, this equivalent Req45 is in series with R3, therefore:

Req345=R3+Req45\\Req345=4+2.22\\Req345=6.22

This Req345 is in parallel with R2, i.e

Req2345=(R2^{-1}+Req345^{-1}  )^{-1}\\ Req2345=(4^{-1}+6.22^{-1}  )^{-1} \\Req2345=2.43

Now this gets in series with R1:

Req12345=R1+Req2345\\Req12345=9+2.43\\Req12345=11.43

Now, the power delivered Ws is:

Ws=Vs*I=\frac{Vs^{2}}{Req}  \\Ws=\frac{10^{2} }{11.43} \\Ws=8.75 Watts

8 0
3 years ago
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