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VikaD [51]
3 years ago
15

A diagram of a closed circuit with power source on the left labeled 12 V, a resistor on the top labeled 1.5 Ohms, a resistor on

the right labeled 2.0 Ohms and a resistor on the bottom labeled 3.0 Ohms.
Calculate the current in the circuit shown.
A

Calculate the voltage across the 3 Ω resistor.
V
Physics
1 answer:
Anon25 [30]3 years ago
3 0

Answer:

A = 1.8

V = 5.4

Explanation:

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Elden [556K]

Answer:

25 degrees above the horizontal.

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In which situation are both the speed and velocity of the car changing?
lubasha [3.4K]
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6 0
3 years ago
Read 2 more answers
A 5.00 kg object oscillates back and forth at the end ofa spring whose spring constant is 49.3 N/m. An obersever istraveling at
defon

Answer:

5.571 sec

Explanation:

angular frequency = √ (k/m) = √ (49.3 / 5) = 3.14 rad/s

Period To = 2π / angular frequency

Period To = 2π/3.14 = 2 × 3.14 / 3.142 = 2.00 sec which you got

T measured by the observer = To / (√ (1 - (v²/c²))) = 2 / √( 1 - 0.871111) = 2 / 0.35901 = 5.571 sec

t=2.00/(1-√((2.80*10^8)^2/(3.00*10^8)^2))= should have been  ( To / (√ (1 - (v²/c²))).  where To = 2.00 sec

8 0
3 years ago
Test questions!!!!!!!!
Pani-rosa [81]

Answer:

B. surface wave

8 0
3 years ago
A sprinter starts from rest and runs with constant acceleration to a top speed of 12m/s in 4.0 seconds.
bagirrra123 [75]

Answer:

  a =  3,0 m/s²

Explanation:

En este ejercicio se pide calcular la aceleracion del cuerpo, usemos las ecuaciones de cinematica en una dimensión.

          v= v₀ + a t

como el corredor parte del reposo si velocidad inicial es cero

           v =  at

           a = v/t

calculemos

          a = 12 /4,0

          a =  3,0 m/s²

4 0
3 years ago
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