Answer:
91.84 m/s²
Explanation:
velocity, v = 600 m/s
acceleration, a = 4 g = 4 x 9.8 = 39.2 m/s^2
Let the radius of the loop is r.
he experiences a centripetal force.
centripetal acceleration,
a = v² / r
39.2 x r = 600 x 600
r = 3600 / 39.2
r = 91.84 m/s²
Thus, the radius of the loop is 91.84 m/s².
Answer:
The distance spring compresses (x) = 0.0811 m
Explanation:
Spring constant (k) = 185 N / m
mass (m) = 1.53 kg
When mass is placed upon the spring the spring force is equal to weight of the mass.
⇒ Spring force (F) = weight of object
⇒ Spring force (F) = k × x
And weight of the object = mg
⇒ k x = mg -----------------(1)
Put all the values in equation (1) we get
⇒ 185 × x = 1.53 × 9.81
⇒ x = 0.0811 m
This the distance spring compresses, when mass is placed upon it.
It has 50kg with a velocity of 1 m/s times the speed of the cart divided by 2 and multiplied by kinectic x plus 5
The answer is C
Hope this help
B. the sum of the protons and the neutrons in one atom of the element
