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Andreyy89
3 years ago
9

A pile driver of mass 5 tonnes falls from a height of 10m onto a pile of mass 8 tonnes There is no rebound on impact as the pile

is driven 20cm into the ground. Determine the common Velocity of hammer and pile after impact.​
Physics
1 answer:
Alchen [17]3 years ago
5 0

Answer:

5. View 31 suppliers of Drop Hammer Pile Driving Rigs on Suppliers. In very soft ... 2 m onto the top of a 140-kg pile, driving it 110 unit into the ground. ... Pilehire have drop hammers from 3ton to 30ton to suit all piling and post jobs ... The DELMAG diesel pile hammer is an extremely rugged and reliable impact hammer .

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Atmospheric pressure decreases with increment in height.<br> give reason​
jekas [21]

Answer:

pressure=height × density×acc due to gravity

so

pressire is directly proportional to height hence it decreses with decrease in height

here air column height is measured upside down so decreases witn increment

7 0
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What is a benefit of a medically supervised rehabilitation program?
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A. Doctors can safely monitor the physical demands of detox

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3 0
3 years ago
I need help on number 4 and 5
Strike441 [17]

4 is G. BB and Bb because that is what you are analyzing the product of.

5 is C. The round shape is obviously a dominant trait since mixing with a wrinkled shape didn't have an effect. The wrinkled shape is recessive.

7 0
4 years ago
This figure shows an all-sky map of the cosmic microwave background recorded by the wmap telescope. how long did this light trav
hichkok12 [17]
The speed of light in a vac uum is 186,282 miles per second<span> (</span>299,792 kilometers per second<span>), and in theory nothing can travel faster than light. In miles per hour, light speed is, well, a lot: about 670,616,629 mph. If you could travel at the speed of light, you could go around the Earth 7.5 times in one second.

I hope my answer has come to your help. God bless you and have a nice day ahead!
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4 0
4 years ago
What is the velocity of a beam of electrons that goes undeflected when moving perpendicular to an electric and magnetic fields.
Charra [1.4K]

Explanation:

Given that,

Electric field, E = 7900 V/m

Magnetic field, B=9.1\times 10^{-3}\ T

(a) Let v is the velocity of a beam of electrons that goes undeflected when moving perpendicular to an electric and magnetic fields. The magnitude of electric force and the magnetic force balance each other as :

qE=qvB

v=\dfrac{E}{B}

v=\dfrac{7900\ V/m}{9.1\times 10^{-3}\ T}

v=8.68\times 10^5\ m/s

(b) Let r is the radius of the electron orbit. The radius of the motion of electron is given by :

r=\dfrac{mv}{qB}

r=\dfrac{9.1\times 10^{-31}\ kg\times 8.68\times 10^5\ m/s}{1.6\times 10^{-19}\ C\times 9.1\times 10^{-3}\ T}

r=5.4\times 10^{-4}\ m

Hence, this is the required solution.

3 0
3 years ago
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