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Andreyy89
3 years ago
9

A pile driver of mass 5 tonnes falls from a height of 10m onto a pile of mass 8 tonnes There is no rebound on impact as the pile

is driven 20cm into the ground. Determine the common Velocity of hammer and pile after impact.​
Physics
1 answer:
Alchen [17]3 years ago
5 0

Answer:

5. View 31 suppliers of Drop Hammer Pile Driving Rigs on Suppliers. In very soft ... 2 m onto the top of a 140-kg pile, driving it 110 unit into the ground. ... Pilehire have drop hammers from 3ton to 30ton to suit all piling and post jobs ... The DELMAG diesel pile hammer is an extremely rugged and reliable impact hammer .

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Which law relates to any pushing or pulling applied to the body to create motion?
STALIN [3.7K]

A force relates to any pushing or pulling applied to the body to create motion.

5 0
3 years ago
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The acceleration due to gravity on earth will decrease as which of the following occurs. The mass of the object decreases. The d
pentagon [3]

Answer:

The distance of the object to the center of the earth increases.

Explanation:

The acceleration due to gravity on Earth is given by:

g=\frac{GM}{r^2}

where

G is the gravitational constant

M is the Earth's mass

r is the distance of the object from the Earth's centre

We notice that:

- g does not depend on the mass of the object

- g is inversely proportional to r

This means that if the distance of the object from the Earth's centre increases, g decreases. So, the correct option is

The distance of the object to the center of the earth increases.

4 0
3 years ago
Explain how to find the acceleration of an object that has one-dimensional horizontal motion.
Nostrana [21]
Acceleration is how much the velocity changes within a period of time so,

Acceleration= is the change in velocity divided by change in time

your units will be m/s squared
7 0
3 years ago
The driver of a 1750 kg car traveling on a horizontal road at 110 km/h suddenly applies the brakes. Due to a slippery pavement,
Alexeev081 [22]

Answer: a=-2.4525 m/s^2

d=s=190.3 m

Explanation:The only force that is stopping the car and causing deceleration is the frictional force Fr

Fr = 25% of weight

W=mg

W=1750*9.81

W=17167.5

Hence

Fr=\frac{25}{100} * -17167.5\\\\Fr=-4291.875 N

Frictional force is negative as it acts in opposite direction

According to newton second law of motion

F=ma

hence

a=Fr/m

a=-4291.875/1750\\a=-2.4525

given

u= 110 km/h

u=110*1000/3600

u=30.55 m/s

to get t we know that final velocity v=0

v^2=u^2+2as\\0=30.55^2-2*2.4525*s\\s=190.34m

3 0
3 years ago
The power in an electrical circuit is given by the equation P= RR, where /is
Rainbow [258]

Answer:D

Explanation:Electric power=I*I*R

=12*12*100

=14400watts

6 0
3 years ago
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