All categories

3 years ago

12.5 kilometers is equivalent to how many meters

2 answers:

6 0

Hey! Thanks for submitting your question to brainly!

The answer is 12,500 meters

To find the conversion from km to meters, you do x1,000

Mrac [35]3 years ago

3 0

1km = 1000m. If you multiply your number in km by 1000 you'll get the answer:

12.5 x 1000 = 12 500m

Hope it helped,

Happy homework/ study/ exam!

You might be interested in

How many carbon atoms are represented by the model below A) 0 B) 3 C) 2 D) 1

Bogdan [553]

Answer:

Option (B) 3.

Explanation:

In the model represented above, the two extreme represent carbon atoms since no other group are attached to it. The joint at the middle also represent carbon atom.

Thus, we can write a more simplify illustration for the model above as

C—C—C

From the above illustration, we can see that the model contains 3 carbon atom.

5 0

2 years ago

How many are molecules ( or formula) in each sample?

andre [41]

Answer:

$4.010 \times 10^{25} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$
$16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

Explanation:

Number of molecules for $55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$

$\text { Firstly molar mass is calculated of } \mathrm{NaHCO}_{3}:$

Atomic mass of Na + H + C + 3(O) = 22.99 + 1.008 + 12.01 + 3 × 16.00 = 84.00 g/mol

$\text { Number of molecules of } \mathrm{NaHCO}_{3} \text { in } 55.93 \text { kg are as follows: }$

$55.93 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} \mathrm{NaHCO}_{3}}{84.00 \mathrm{gm} \mathrm{NaHCO}_{3}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number }\right)$

$=4.010 \times 10^{26} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}$

Number of molecules for for $\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

$\text { Firstly molar mass is calculated of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

= Atomic mass of 3(Na) + P + 4(O)

= 3(22.99) + 30.97 + 4(16.00) = 163.94 g/mol

$459 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} N a_{3} P O_{4}}{163.94 \mathrm{gm} N a_{3} P O_{4}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number) } / 1 \mathrm{mol}\right.$

$=16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}$

8 0

3 years ago

What is the number of moles in 15.0 g AsH3?

pentagon [3]

We are given with the mass of Arsine ( $AsH_{3}$

The mass of arsine is 15g

there is a relation between moles, mass and molar mass of any compound which is

$moles=\frac{mass}{molarmass}$

The molar mass of Arsine = atomic mass of As + 3X atomic mass of H

the molar mass of Arsine = 74.92 + 3X 1 = 77.92 g/mol

Let us calculate the moles as

$moles=\frac{15}{77.92}=0.192mol$

7 0

2 years ago

Aldo cannot get the answer to a chemistry problem, even after sitting at his desk for an hour. He gets up and goes for a walk. S

Alex17521 [72]

Answer:

Insight

Explanation:

Insight is the understanding of a specific cause and effect within a specific context. The term insight can have several related meanings:

a piece of information
the act or result of understanding the inner nature of things or of seeing intuitively (called noesis in Greek)
an introspection
the power of acute observation and deduction, discernment, and perception, called intellection or noesis
an understanding of cause and effect based on identification of relationships and behaviors within a model, context, or scenario (see artificial intelligence)

An insight that manifests itself suddenly, such as understanding how to solve a difficult problem, is sometimes called by the German word Aha-Erlebnis. The term was coined by the German psychologist and theoretical linguist Karl Bühler. It is also known as an epiphany, eureka moment or (for cross word solvers) the penny dropping moment (PDM). Sudden sickening realizations identifying a problem rather than solving it, so Uh-oh rather than Aha moments are further seen in negative insight. A further example of negative insight is chagrin which is annoyance at the obviousness of a solution missed up until the point of insight.

6 0

3 years ago

How many moles of carbon dioxide gas should be produced when 10.0 g of C2H6 are combusted at STP?

Finger [1]

Answer:

0.665 moles of CO₂

Explanation:

The balance chemical equation for the combustion of Ethane is as follow:

2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Step 1: Calculate moles of C₂H₆ as;

Moles = Mass / M.Mass

Putting values,

Moles = 10.0 g / 30.07 g/mol

Moles = 0.3325 moles

Step 2: Calculate Moles of CO₂ as;

According to balance chemical equation,

2 moles of C₂H₆ produced = 4 moles of CO₂

So,

0.3325 moles of C₂H₆ will produce = X moles of CO₂

Solving for X,

X = 0.3325 mol × 4 mol ÷ 2 mol

X = 0.665 moles of CO₂

3 0

2 years ago