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2 years ago

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above the ground and fired. The water stream from the gun hits the ground a horizontal distance of 7.3 m from the muzzle. Find t

he gauge pressure of the water gun’s reservoir at the instant when the gun is fired. Assume that the speed of the water in the reservoir is zero and that the water flow is steady. Ignore both air resistance and the height difference between the reservoir and the muzzle.

1 answer:

FromTheMoon [43]2 years ago

5 0

Answer:

$P_g=1.1373Mpa$

Explanation:

A hand-pumped water gun is held level at a height of 0.75 m, this part miss of the question so now:

h=0.75 m

x=7.3 m

$h=\frac{1}{2}*a*t^2$

$a=g$

$t=\sqrt{\frac{2*h}{g}}=\sqrt{\frac{2*0.75m}{9.8m/s^2}}$

$t=0.153s$

$v=\frac{x}{t}=\frac{7.3m}{0.153s}=47.6m/s$

Gauge Pressure can be find

$P_g=\frac{1}{2}*1000*v^2$

$P_g=\frac{1}{2}*1000*(47.69m)^2$

$P_g=1.1373Mpa$

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What gravitational force does the moon produce

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Answer:

$1.94\cdot 10^{20} N$

Explanation:

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r is the separation between the objects

The gravitational force is always attractive.

In this problem, we have:

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$m_2 = 7.34\cdot 10^{22} kg$ is the mass of the Moon

$r=3.88\cdot 10^8 m$ is the separation between the Earth and the Moon

Therefore, the gravitational force between them is

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Suppose light from a 632.8 nm helium-neon laser shines through a diffraction grating ruled at 520 lines/mm. How many bright line

Leya [2.2K]

Answer:

1 bright fringe every 33 cm.

Explanation:

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where

m is the order of the maximum

$\lambda$ is the wavelength of the light

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Here we have:

$\lambda=632.8 nm = 632.8\cdot 10^{-9} m$ is the wavelength of the light

D = 1 m is the distance of the screen (not given in the problem, so we assume it to be 1 meter)

$n=520 lines/mm$ is the number of lines per mm, so the spacing between two lines is

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Therefore, substituting m = 1, we find:

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3 years ago

A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical ener

defon

Complete question:

A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J. Find

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Answer:

(a) the force constant of the spring = 47 N/m

(b) the amplitude of the motion = 0.292 m

Explanation:

Given;

mass of the spring, m = 200g = 0.2 kg

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total mechanical energy of the spring, E = 2 J

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E = ¹/₂kA²

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Answer:

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