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Mama L [17]
3 years ago
11

When the above equation is balanced the coefficients in order are

Chemistry
1 answer:
Softa [21]3 years ago
4 0
The reaction is as follow,

                   Ca(OH)₂  +  Al₂(SO₄)₃    →     CaSO₄  +  Al(OH)₃

Ca are balance on both sides, 

There are 2 Al at left side and one at right so, multiply Al(OH)₃ by 2 to balance,
So,
                   Ca(OH)₂  +  Al₂(SO₄)₃    →     CaSO₄  +  2 Al(OH)₃

Now, Ca and Al are balanced, now balance SO₄, which is 3 at left hand side and one at right hand side, so multiply CaSO₄ on right side by 3, so,

                   Ca(OH)₂  +  Al₂(SO₄)₃    →     3 CaSO₄  +  2 Al(OH)₃

Again Ca got imbalance, so multiply Ca(OH)₂ by 3 to balance Ca, So,

                   3 Ca(OH)₂  +  Al₂(SO₄)₃    →     3 CaSO₄  +  2 Al(OH)₃

The Equation is balance now with respect to every element.

Result:
          The Ratio is 3 : 1 : 3 : 2, so, Option-G is correct.
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Use pOH = -log₁₀ [OH-]

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pOH = -log₁₀ [OH-]

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3 years ago
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6 0
3 years ago
A beaker filled with freshwater has a p h balance of 6.65. geraldo wants to model the effect of acids on the ph of water for a g
kvv77 [185]

Geraldo can add a pollutant with slightly basic nature so he will have a solution of neutral pH of 7.

<h3>What is pH?</h3>

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The pH of 6.5 means that the solution is acidic.

By adding a pollutant which is slightly basic in nature, Geraldo will have a solution of neutral pH which is a pH of 7.

Learn more about pH at: brainly.com/question/24595796

4 0
2 years ago
How many grams of CuSO4 are there in 100.0 g of hydrate? How many moles?
lapo4ka [179]
The hydrate form of CuSO4 has 5 water molecules (CuSO4-5H20) copper (II) Sulfate pentahydrate or commonly known as blue vitriol. 

To solve, the following molar masses are to be known. 
CuSO4.5H2O (hydrate)  - 249.7g/mole
CuSO4 (anhydrous) -159.6g/mole
Also there molar ratio of the hydrate and CuSO4 is 1. 

the mass of the hydrate is to be divided by the molar mass of the hydrate then multiplied by the ratio (1) to get the moles of hydrate and multiplied by the molar mass of the anhydrous to get the mass in grams. 

moles = (100g/249.7)*1 =  0.4 moles hydrate
grams = 0.4*159.6 =  64.9 grames hydrate


8 0
3 years ago
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