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Mama L [17]
3 years ago
11

When the above equation is balanced the coefficients in order are

Chemistry
1 answer:
Softa [21]3 years ago
4 0
The reaction is as follow,

                   Ca(OH)₂  +  Al₂(SO₄)₃    →     CaSO₄  +  Al(OH)₃

Ca are balance on both sides, 

There are 2 Al at left side and one at right so, multiply Al(OH)₃ by 2 to balance,
So,
                   Ca(OH)₂  +  Al₂(SO₄)₃    →     CaSO₄  +  2 Al(OH)₃

Now, Ca and Al are balanced, now balance SO₄, which is 3 at left hand side and one at right hand side, so multiply CaSO₄ on right side by 3, so,

                   Ca(OH)₂  +  Al₂(SO₄)₃    →     3 CaSO₄  +  2 Al(OH)₃

Again Ca got imbalance, so multiply Ca(OH)₂ by 3 to balance Ca, So,

                   3 Ca(OH)₂  +  Al₂(SO₄)₃    →     3 CaSO₄  +  2 Al(OH)₃

The Equation is balance now with respect to every element.

Result:
          The Ratio is 3 : 1 : 3 : 2, so, Option-G is correct.
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Read 2 more answers
5Br−+BrO3−+6H+→3Br2+3H2O
sashaice [31]

Explanation :

The balanced chemical reaction is,

5Br^-+BrO_3^-+6H^+\rightarrow 3Br_2+3H_2O

The expression for the rates of consumption of the reactants are:

The rate of consumption of Br^- = -\frac{1}{5}\frac{d[Br^-]}{dt}

The rate of consumption of BrO_3^- = -\frac{d[BrO_3^-]}{dt}

The rate of consumption of H^+ = \frac{1}{6}\frac{d[H^+]}{dt}

The expression for the rates of formation of the products are:

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5 0
2 years ago
What is the mole fraction of NaOH in an aqueous solution that
astraxan [27]

Answer:

The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

Explanation:

We are given that

Aqueous solution that contains 22.9% NaOH by mass means

22.9 g NaOH in 100 g solution.

Mass of NaOH(WB)=22.9 g

Mass of water =100-22.9=77.1

Na=23

O=16

H=1.01

Molar mass of NaOH(MB)=23+16+1.01=40.01

Number of moles =\frac{Given\;mass}{Molar\;mass}

Using the formula

Number of moles of  NaOH(n_B)=\frac{W_B}{M_B}=\frac{22.9}{40.01}

n_B=0.572moles

Molar mass of water=16+2(1.01)=18.02g

Number of moles of water(n_A)=\frac{77.1}{18.02}

n_A=4.279 moles

Now, mole fraction of NaOH

=\frac{n_B}{n_B+n_A}

=\frac{4.279}{0.572+4.279}

=0.882

Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

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