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3 years ago

11

When the above equation is balanced the coefficients in order are

1 answer:

Softa [21]3 years ago

4 0

The reaction is as follow,

Ca(OH)₂ + Al₂(SO₄)₃   → CaSO₄ + Al(OH)₃

Ca are balance on both sides,

There are 2 Al at left side and one at right so, multiply Al(OH)₃ by 2 to balance,
So,
Ca(OH)₂ + Al₂(SO₄)₃   → CaSO₄ + 2 Al(OH)₃

Now, Ca and Al are balanced, now balance SO₄, which is 3 at left hand side and one at right hand side, so multiply CaSO₄ on right side by 3, so,

Ca(OH)₂ + Al₂(SO₄)₃   → 3 CaSO₄ +  2 Al(OH)₃

Again Ca got imbalance, so multiply Ca(OH)₂ by 3 to balance Ca, So,

3 Ca(OH)₂ + Al₂(SO₄)₃   → 3 CaSO₄ +  2 Al(OH)₃

The Equation is balance now with respect to every element.

Result:
The Ratio is 3 : 1 : 3 : 2, so, Option-G is correct.

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Read 2 more answers

5Br−+BrO3−+6H+→3Br2+3H2O

sashaice [31]

Explanation :

The balanced chemical reaction is,

$5Br^-+BrO_3^-+6H^+\rightarrow 3Br_2+3H_2O$

The expression for the rates of consumption of the reactants are:

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2 years ago

What is the mole fraction of NaOH in an aqueous solution that

astraxan [27]

Answer:

The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

Explanation:

We are given that

Aqueous solution that contains 22.9% NaOH by mass means

22.9 g NaOH in 100 g solution.

Mass of NaOH(WB)=22.9 g

Mass of water =100-22.9=77.1

Na=23

O=16

H=1.01

Molar mass of NaOH(MB)=23+16+1.01=40.01

Number of moles = $\frac{Given\;mass}{Molar\;mass}$

Using the formula

Number of moles of NaOH $(n_B)=\frac{W_B}{M_B}=\frac{22.9}{40.01}$

$n_B=0.572moles$

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Number of moles of water $(n_A)=\frac{77.1}{18.02}$

$n_A=4.279 moles$

Now, mole fraction of NaOH

= $\frac{n_B}{n_B+n_A}$

$=\frac{4.279}{0.572+4.279}$

=0.882

Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

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