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morpeh [17]
4 years ago
9

What is the molarity of a solution that contains 4.13g of magnesium bromide in 0.845 L of solution

Chemistry
1 answer:
nevsk [136]4 years ago
4 0
RMM magnesium bromide=184
184g=1 mol
4.13g will have=4.13*1/184=0.022mols
molarity=0.022/0.845=0.027M

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Ganezh [65]

Answer: I think it represents the SiO

Explanation:

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3 years ago
The variables _______ and ________ affect the gravitational force between objects.
anastassius [24]
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A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from
sweet-ann [11.9K]

Answer:

T_i~=163.1 ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

<u>Initial temperature of gold= Unknow</u>

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the <u>heat equation</u>:

Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT

Q_A_u=m_A_u*Cp_A_u*deltaT

We can relate these equations if we take into account that <u>all heat of gold is transfer to the water</u>, so:

m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT

Now we can <u>put the values into the equation</u>:

60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)

Now we can <u>solve for the initial temperature of gold</u>, so:

T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20

T_i~=163.1 ºC

I hope it helps!

5 0
3 years ago
How many half lives would pass if a mass of copper-66 decayed for 51 minutes? The half life of Cu-66 is 5.10 minutes.
Sveta_85 [38]
Divide 51 by 5.1, it's 10 half lives
4 0
3 years ago
HELP ASAP!!!!!!
blondinia [14]

2, 4, 1

Explanation:

We have the following chemical reaction:

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To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

So the balanced chemical equation is:

2 Ag₂O → 4 Ag + O₂

Learn more about:

balancing chemical equations

brainly.com/question/14112113

brainly.com/question/14187530

#learnwithBrainly

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