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Using the impulse-momentum theorem and taking this down as positive, we will get:
FΔt = Δp
F = Δp / Δt
= m(v - v₀) / t
= 0.056kg [13m/s - (- 20m/s) / 0.00125s
= 1478.4 N when properly rounded off is the answer we are looking for in this problem.
Answer:
14.7 Volt
Explanation:
C1 = 2.74 F, C2 = 7.46 F, C3 = 10.1 F
Here C1 and C3 are in parallel
So, Cp = C1 + C3 = 2.74 + 10.1 = 12.84 F
Now Cp and C2 are in series
1 / C = 1 / Cp + 1 / C2
1 / C = 1 / 12.84 + 1 / 7.46
C = 4.72 F
Let q be the total charge
q = C V = 4.72 x 40 = 188.8 C
Voltage across C2
V2 = q / C2 = 188.8 / 7.46 = 25.3 V
Voltage across C2 or c3
V' = V - V2 = 40 - 25.3
V' = 14.69
V' = 14.7 Volt
Answer:
false
Explanation:
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