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2 years ago

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A gadget of mass 21.85 kg floats in space without motion. Because of some internal malfunction, the gadget violently breaks up i

nto 3 fragments flying away from each other. The first fragment has mass m1 = 6.42 kg and speed v1 = 6.8 m/s while the second fragment has mass m2 = 8.26 kg and speed v2 = 3.54 m/s. The angle between the velocity vectors ~v1 and ~v2 is θ12 = 64 ◦ . What is the speed v3 of the third fragment? Answer in units of m/s.

1 answer:

BaLLatris [955]2 years ago

6 0

Answer:

$v_3=8.622\ m.s^{-1}$

Explanation:

Given:

mass of the gadget, $m=21.85\ kg$

mass of fragment 1, $m_1=6.42\ kg$

mass of fragment 2, $m_2=8.26\ kg$

velocity of fragment 1, $v_1=6.8\ m.s^{-1}$

velocity of fragment 2, $v_2=3.54\ m.s^{-1}$

angle between the velocity 1 & 2, $\theta=64\ ^{\circ}$

<u>Now the mass of the third part:</u>

$m_3=m-(m_1+m_2)$

$m_3=21.85-(6.42+8.26)$

$m_3=7.17\ kg$

<u>The momentum of the gadget before and after collision is equal:</u>

$m_3.v_3=m_1.v_1\cos\ \frac{\theta}{2} +m_2.v_2\cos \frac{\theta}{2}$

$7.17\times v_3=(6.42\times6.8+8.26\times3.54)\times \cos \frac{64}{2}$

$v_3=8.622\ m.s^{-1}$

Refer schematic for more clarity.

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