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Rom4ik [11]
3 years ago
8

Please help me!!!

Physics
2 answers:
natima [27]3 years ago
7 0
<span>It is only possible if the fences has same voltage but different type of electric voltages(i.e. one, Ac voltage & another, Dc voltage). 

As having the same magnitude they varies in their properties. among them Ac has sinosuidal variation of voltage. that's why, Ac has large amplitude then the mean voltage(rms). 

+ Dc has constant magnitude. e.g. at home we know the recomended ac voltage is 220v(rms) but it raises upto 311


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
Leto [7]3 years ago
5 0

The voltage is the powerful force that will cause a superior or smaller electrical current dependent on the electrical resistance of the hurdles to the flow of electricity.

If one electric barrier has a greater confrontation to the stream of electricity, then with the  formula we can construe that the current for the fence with the greater resistance will be smaller than for the fence with smaller resistance which will be greater.

The electrical shockwave rest on on the electric current which depends on the electrical resistance

hope it helps

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An object is placed a distance of twice the focal length away from a diverging lens. What is the magnification of the image?
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Answer:

1/3

Explanation:

We can solve the problem by using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

Here we have a divering lens, so the focal length must be taken as negative (-f). Moreover, we know that the object is placed at a distance of twice the focal length, so

p=2f

So we can find q from the equation:

\frac{1}{q}=\frac{1}{(-f)}-\frac{1}{p}=-\frac{1}{f}-\frac{1}{2f}=-\frac{3}{2f}\\q=-\frac{2}{3}f

Now we can find the magnification of the image, given by:

M=-\frac{q}{p}=-\frac{-\frac{2}{3}f}{2f}=\frac{1}{3}

8 0
4 years ago
A body of mass 50kg is placed on a wall of height 1.5m what is the potential energy​
DiKsa [7]

Answer:

PE=mgh

=50×1.5×9.8

=735

Explanation:

need thanks and make me brainiest if it helps you

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Part 2

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