Answer:
I need this for may schooling
Since the new distance is 3 times the old distance,
the new force is (1/3²) = 1/9th of the old force.
That's kind-of Choice-D, but I really don't like the way choice-D is worded.
"9 times smaller" is really pretty meaningless.
The unit of acceleration would be m/s² :)
I believe that is true. Anaerobic means without (much) Oxygen. This usually builds up lactic acid in muscles.
Answer:
The speed is 
Explanation:
From the question we are told that
The length of the wire is 
The mass density is 
The tension is 
Generally the speed of the transverse cable is mathematically represented as

substituting values

