All categories

4 years ago

A circuit with which components has a current with the greatest voltage?

Physics

2 answers:

kotykmax [81]4 years ago

8 0

Answer: it’s A

Explanation: :I

Ymorist [56]4 years ago

7 0

The components in a circuit don't determine the voltages in it.
The voltages are all determined by the battery or power supply
that energizes the circuit.

You might be interested in

PLZ HELP ME NOW PLZ I NEED THE ANSWER NOW. which statement describes the correct charges of subatomic particles?

Lapatulllka [165]

Are there choices that come with this question?

6 0

3 years ago

Read 2 more answers

The speed or celerity of deep-water waves... A. increases with increasing water depth B. increases as water becomes blue in colo

antoniya [11.8K]

Answer:

Explanation:

The speed or celerity of deep-water waves increases with increasing water depth.

With increase in depth, the pressure inside the increases as p=ρgh.

And with this increase in pressure force associated with waves increase because force is directly proportional to the pressure. Now greater the force greater will be accleration and greater velocity is obtained.

4 0

3 years ago

The picture shows two different species of mammals that use wings to glide among tree tops. However, scientists theorize that th

AlekseyPX

Answer:

Explanation:

6 0

3 years ago

Read 2 more answers

Un tranvía que parte del reposo adquiere al cabo de 20 m recorridos con movimiento uniformemente acelerado, la velocidad de 36 k

Arturiano [62]

Answer:

50m

Explanation:

sbdjdkdjdb dndjdk nsbdkd jsksk dbdj dndj

4 0

3 years ago

The work function of a metal surface is 4.80 × 10-19 J. The maximum speed of the electrons emitted from the surface is vA = 7.7

poizon [28]

Answer:

$\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=3.32344\times 10^{-7}\ m$

Explanation:

h = Planck's constant = $6.63\times 10^{-34}\ m^2kg/s$

c = Speed of light = $3\times 10^8\ m/s$

m = Mass of electron = $9.11\times 10^{-31}\ kg$

$W_0$ = Work function = $4.8\times 10^{-19}\ J$

$v_A$ = Velocity of A particle = $7.7\times 10^5\ m/s$

$v_B$ = Velocity of B particle = $5.1\times 10^5\ m/s$

The wavelength is given by

$\lambda=\frac{hc}{\frac{1}{2}mv^2+W_0}$

$\lambda_A=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(7.7\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_A=2.65177\times 10^{-7}\ m$

The wavelength $\lambda_A=2.65177\times 10^{-7}\ m$

$\lambda_B=\frac{6.63\times 10^{-34}\times 3\times 10^8}{\frac{1}{2}9.11\times 10^{-31}(5.1\times 10^5)^2+4.8\times 10^{-19}}\\\Rightarrow \lambda_B=3.32344\times 10^{-7}\ m$

The wavelength $\lambda_B=3.32344\times 10^{-7}\ m$

5 0

4 years ago