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Yanka [14]
3 years ago
11

A truck travels up a hill with a 5.7° incline. The truck has a constant speed of 22 m/s. What is the horizontal component of the

truck’s velocity? Answer in units of m/s.

Physics
1 answer:
tester [92]3 years ago
8 0

Answer:

The horizontal component of the velocity is 21.9 m/s.

Explanation:

Please see the attached figure for a better understanding of the problem.

Notice that the vector v and its x and y-components (vx and vy) form a right triangle. Then, we can use trigonometry to find the magnitude of vx, the horizontal component of the velocity.

To find vx, let´s use the following trigonometric rule of right triangles:

cos α = adjacent / hypotenuse

cos 5.7° = vx / 22 m/s

22 m/s · cos 5.7° = vx

vx = 21.9 m/s

The horizontal component of the velocity is 21.9 m/s.

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In which scenario does radiation occur? warming soup on a stove drying towels at the beach cooking eggs in boiling water warming
shepuryov [24]

Answer: drying towels at the beach.

Explanation:

Radiation simply has to do with the energy that is gotten from a particular source and then goes through some materials. It simply means the way energy is being transmitted as waves or heat through a certain medium.

From the options given, the scenario whereby a radiation takes place is when drying towels on the beach.

8 0
3 years ago
Read 2 more answers
Joffrey talks and moves slowly. When asked a question, he answers slowly in monotone monosyllables, if he answers at all. Joffre
lana [24]

Answer:

R.E.T.A.R.D.A.T.I.O.N

Explanation:

It won't let me spell it normal

7 0
3 years ago
A rock is thrown horizontally off a cliff with an initial speed of 3 m/s. The initial position of the rock is 10 meters above th
Valentin [98]

Answer:

<em>1.43 s.</em>

Explanation:

Using one of the equations of motion,

S = ut + 1/2gt².......................... Equation 1

Where S = height of the cliff, u = initial velocity, t = time, g = acceleration due to gravity.

<em>Note: When the rock begins to fall from the maximum height, u = 0 m/s, g = positive</em>

<em>Given: S = 10 m, u = 0 m/s</em>

<em>Constant: g = 9.8 m/s²</em>

<em>Substituting these values into equation,</em>

<em>10 = 0(t) + 1/2(9.8)(t²)</em>

<em>10 = 0 + 4.9t²</em>

<em>t² = 10/4.9</em>

<em>t² = 100/49</em>

<em>t = √(100/49)</em>

<em>t = 10/7</em>

<em>t = 1.43 s.</em>

<em>Thus the rock spend 1.43 s in air</em>

3 0
3 years ago
Hey guys! Am I right? Thanks!
worty [1.4K]

Answer:

the correct answer is reduce friction

5 0
3 years ago
A truck with a mass of 1.5 x 103 kg accelerates to a speed of 18.0 m/s in 12.0 s from a dead stop. Assume that the force of resi
Yakvenalex [24]
Power = Net Force x velocity
Net force = driving force - force of resistance
Driving force = mass x acceleration
Acceleration = (final velocity - initial velocity) / time
Acceleration = (18 - 0) / 12 = 1.5 m/s²
Driving force = 1.5 x 10³ x 1.5
= 2250 N
Net force = 2250 - 400
= 1850
Power = 1850 x 18
= 3.33 x 10⁴ Watts
3 0
3 years ago
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