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Softa [21]
3 years ago
12

A generic gas, x, is placed in a sealed glass jar and decomposes to form gaseous y and solid z. 2x(g)â½ââây(g)+z(s) how are thes

e equilibrium quantities affected by the initial amount of x(g) placed in the container? assume constant temperature.
Chemistry
1 answer:
Elan Coil [88]3 years ago
3 0
The chemical equation given is:

<span>2x(g) ⇄ y(g)+z(s)</span>

Answer: the higher the amount of x(g) the more the forward reacton will occur and the higher the amounts of  products y(g) and z(s) will be obtained at equilibrium.

Justification:

As Le Chatellier's priciple states, any change in a system in equilibrium will be compensated to restablish the equilibrium.

The higher the amount, and so the concentration, of X(g), the more the forward reaction will proceed to deal witht he high concentration of X(g), leading to an increase on the concentration of the products y(g) and z (s).
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Two positively charged objects (N pole) are separated by a large distance. One of the positively charged objects (N pole) is rep
Eddi Din [679]

Answer:

B

Explanation:

Applying law of electrostatic which states that like charges repel each other and unlike charges attract each other

N and S are unlike charges that turn and make the former repulsive force (due to two like charges N and N)to <em>reduce</em> and attractive force between N and S to <em>increa</em><em>se</em>

6 0
3 years ago
What is 5.73 moles in grams
Pani-rosa [81]

I calculated is and the answer is 1272.0600000000002.

I really don't know how to explain it

5 0
3 years ago
Rank the solutions below in order of increasing acidity. (Drag and drop into the appropriate area)
Vladimir79 [104]

Answer:

0.1 M NaOH, 3 M NH3, 0.01 M CH3COOH, 0.01 M H2SO4, 0.1 M HCl

Explanation:

Strong acids are more acids than weak acids. In the same way, strong bases are more basic than weak bases that are in the same concentration.

Then, the more concentrated acid or base will be more acidic or basic.

CH3COOH. Weak acid

NaOH. Strong base

H2SO4. Strong acid

NH3. Weak base.

HCl. Strong acid

The less acid (More basic):

<h3>0.1 M NaOH, 3 M NH3, 0.01 M CH3COOH, 0.01 M H2SO4, 0.1 M HCl</h3>

Strong base, weak base, weak acid, diluted strong acid, undiluted strong acid

7 0
3 years ago
Give the name of reaction in the<br> preparation of alkene from alcohol<br> compounds.
pickupchik [31]

Dehydration to alkenes!

3 0
3 years ago
I have 50.00 mL of 0.100 M ethyl amine (C2H5NH2). I gradually add a solution of 0.025 M nitric acid (HNO3) to the ethyl amine so
sergeinik [125]

Answer:

4.00 is the pH of the mixture

Explanation:

The ethyl amine reacts with HNO3 as follows:

C2H5NH2 + HNO3 → C2H5NH3⁺ + NO3⁻

To solve this question we need to find the moles of ethyl amine and the moles of HNO3:

<em>Moles C2H5NH2:</em>

0.0500L * (0.100mol/L) = 0.00500 moles ethyl amine

<em>Moles HNO3:</em>

0.201L * (0.025mol/L) = 0.005025 moles HNO3

That means HNO3 is in excess. The moles in excess are:

0.005025 moles HNO3 - 0.00500 moles ethyl amine =

2.5x10⁻⁵ moles HNO₃

In 50 + 201mL = 251mL = 0.251L:

2.5x10⁻⁵ moles HNO₃ / 0.251L = 9.96x10⁻⁵M = [H+]

As pH = -log [H+]

pH = -log 9.96x10⁻⁵M

pH = 4.00 is the pH of the mixture

6 0
3 years ago
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