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otez555 [7]
2 years ago
11

An example of a solution that is formed endothermically is the one used in

Chemistry
1 answer:
Makovka662 [10]2 years ago
3 0

Cold Packs

<u>Explanation:</u>

Endothermic reactions are reactions in which heat is absorbed from the surroundings and the container in which the reaction takes place is said to be very cold. In cold packs, ammonium nitrate is used, is dissolved in solution is said to be an example of endothermic reaction, in this the heat energy is absorbed from the surroundings. In this the solute increases the solubility with the rise in temperature, and also used in cold packs.

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100 Points! ALSO WILL MARK BRAINLIST IF 100% CORRECT AND HELPFUL !!
Marrrta [24]
<h3><u>Answer</u>;</h3>

= 226 Liters of oxygen

<h3><u>Explanation</u>;</h3>

We use the equation;

LiClO4 (s) → 2O2 (g) + LiCl, to get the moles of oxygen;

Moles of  LiClO4;

(500 g LiClO4) / (106.3916 g LiClO4/mol)

= 4.6996 moles

Moles of oxygen;

But, for every 1 mol LiClO4, two moles of O2 are produced;

= 9.3992 moles of Oxygen

V = nRT / P

= (9.3992 mol) x (8.3144621 L kPa/K mol) x (21 + 273) K / (101.5 kPa)

= 226 L of oxygen

5 0
3 years ago
based on the positions in the periodic table, which two elements would mostly readily combine to make a stable compound
Advocard [28]

Elements that there Electrons equal a multiple of 8 because then they become a noble gas.


4 0
3 years ago
I REALLY NEED HELP!! Is rubbing alcohol polar, non polar or ionic? Does it mix with water? Does it mix with vinegar?
Taya2010 [7]

Answer:

You can mix both with rubbing alcohol, and rubbing alcohol is ionic.

Explanation:

To mix them together:

Combine 1 cup rubbing alcohol, 1 cup water, and 1 tablespoon of white vinegar into a spray bottle. The solution can kill germs and clean counters, according to Reader's Digest.

Rubbing alcohol is both polar and iconic.

Hope that this helps you and have a great day :)

4 0
3 years ago
An 80.0g sample of an unknown metal is at an initial temperature of 55.5oC. Afer 540 J of energy is absorbed by the metal, the t
Lunna [17]

Answer:

Specific heat of metal = 0.26 j/g.°C

Explanation:

Given data:

Mass of sample = 80.0 g

Initial temperature = 55.5 °C

Final temperature = 81.75 °C

Amount of heat absorbed = 540 j

Specific heat of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  81.75 °C - 55.5 °C

ΔT =  26.25 °C

540 j = 80 g × c × 26.25 °C

540 j = 2100 g.°C× c

540 j / 2100 g.°C = c

c = 0.26 j/g.°C

7 0
2 years ago
If there is a total of 100J of
likoan [24]

Answer:

60j because 100-60=40j

6 0
3 years ago
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