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ahrayia [7]
3 years ago
5

Elena makes the table below to determine the number of atoms of each element in the chemical formula 3(NH4)2SO4.

Chemistry
2 answers:
Ymorist [56]3 years ago
5 0

Answer:

plqojs then came back and her story about how the ocean had become toper for her own purposes and share the ocean and the mosquitoes and it that way in notebook life that they were never able of English orto make the ocean view the mosquitoes in the first place they would have to make it to.

eimsori [14]3 years ago
3 0

Answer:

C)she should not have multiplied the sulfur atoms by the subscript 4

I got u guy on top u weird

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How many cm is 0.375 ft.​
ivann1987 [24]

Answer:

11.43 cm

Explanation:

8 0
2 years ago
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Assuming equal concentrations, arrange these solutions by pH.
LenKa [72]

Answer:

Highest pH(most basic)

Sr(OH)2(aq)

KOH (aq)  

NH3(aq)

HF (aq)  

HClO4(aq)

Lowest pH(most acidic)

Explanation:

The concentration of H+ ion will determine the pH of a solution. The pH actually reflects the ratio of H+ ion and OH- since both of them can combine into water. Solution with more H+ ion will have a lower pH and called acidic, while more OH- will have high pH and be called basic. Strong acid/base will be ionized more than weak acid/base.

Sr(OH)2(aq) = strong base, release 2 OH- ion per mole

KOH (aq) = Strong base, release 1 OH- per mole

NH3(aq) = weak base, release less than 1 OH- per mole

HF (aq) =strong acid, release 1 H+ per mole

HClO4(aq) = stronger acid, release 1 H+ per mole

8 0
3 years ago
The concentration of ozone in a sample of air that has a partial pressure of O3 of 0.33 torr and a total pressure of air of 695
Goryan [66]

Answer:

0.047 %

Explanation:

Step 1: Given data

  • Partial pressure of ozone (pO₃): 0.33 torr
  • Total pressure of air (P): 695 torr

Step 2: Calculate the %v/v of ozone in the air

Air is a mixture of gases. We can find the %v/v of ozone (a component) in the air (mixture) using the following expression.

<em>%v/v = pO₃/P × 100%</em>

%v/v = 0.33 torr/695 torr × 100%

%v/v = 0.047 %

8 0
3 years ago
Twenty-four grams of magnesium metal reacts with sixteen grams of oxygen gas to form magnesium oxide. According to the law of co
DedPeter [7]
The law of conservation of mass dictates that the total mass of reactants must be equal to the total mass of the products. Thus:
mass(MgO) = mass(Mg) + mass(O)
mass(MgO) = 24 + 16
mass(MgO) = 40 g

The third option is correct.
4 0
3 years ago
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Zina [86]

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4 0
3 years ago
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