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LuckyWell [14K]
3 years ago
12

Consider the following situation, in which a compass is influenced by not only the force of Earth's magnetic field, but also an

additional applied force.
1. Which of the following is true of the angle of deflection of the compass relative to FEarth if FEarth > FApplied?

a. The angle of deflection will be exactly 45°
b. The angle of deflection will be greater than 90°
c. The angle of deflection will be less than 45°
d. The angle of deflection will be exactly 0°
e. The angle of deflection will be greater than 45° but less than 90°

2. Which of the following is true of the angle of deflection of the compass relative to FEarth if FEarth < FApplied?

a. The angle of deflection will be exactly 45°
b. The angle of deflection will be greater than 90°
c. The angle of deflection will be less than 45°
d. The angle of deflection will be exactly 0°
e. The angle of deflection will be greater than 45° but less than 90°
Physics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

1) The angle of deflection will be less than 45° ( C )

2)  The angle of deflection will be greater than 45° but less than 90° ( E )

Explanation:

1) Assuming that the force applied  has a direction which is perpendicular to the Earth's magnetic field

∴ Fearth > Fapplied   hence the angle of deflection will be < 45°

2) when the Fearth < Fapplied

the angle of deflection will be :   > 45°  but  < 90°

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What is the root mean square speed of an As4 particle as it is sublimed? (Assume at high temperatures arsenic acts like an ideal
Norma-Jean [14]

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It can be calculated:

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5 0
3 years ago
THE RELATIVE ANGLE AT THE KNEE CHANGES FROM 0O TO 85O DURING THE KNEE FLEXION PHASE OF A SQUAT EXERCISE. IF 10 COMPLETE SQUATS A
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Answer: angular distance = 1700° and 29.7 rad

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To explain this, i will give a breakdown of this works.

we are asked to find both the angular distance and displacement the knee undergo.

Ok to get the distance of the knee, we would first take note that for one to squat down and get back up, the knee would travel through 85° of flexion to gpo down, and also through another 85° of extension to return standing (upright). So, the actual angular distance of the squat is 170°.

taking ten squats, the knee would have to go through 170° motion times 10 i.e;

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now converting this distance to radians since we will be required to have our answer in both degree and rad.

Given that 2pi = 360°, it means that one degree will give 57.3°;

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∅ (rad) = 1170° * 2π/360°  = 29.7 rad

∅ (rad) = 29.7 rad

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cheers i hope this helps!!!!

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5 0
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