How many moles of CO are present in 35.88 L of the gas?
1 answer:
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Answer:
91.1835 nm
Explanation:
Given that the ionization energy of the oxygen molecule = 1314 kJ/mol
It means that
1 mole of oxygen molecules can be ionized by the energy = 1314 kJ = 1314000 J
1 mole of molecules contains 6.022 × 10²³ atoms
So,
6.022 × 10²³ atoms of oxygen molecules can be ionized by the energy = 1314000 J
1 atom require of energy
Energy =
Also
Where,
h is Plank's constant having value
c is the speed of light having value
is the wavelength
So,
Also,
So, wavelength = 91.1835 nm