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natima [27]
1 year ago
5

A solution is formed by dissolving 29.2 grams of sodium chloride (NaCl) in 3.0 liters of solution. The molar mass of NaCl is 58.

5 g/mol.What is the molarity of the solution?

Chemistry
1 answer:
astraxan [27]1 year ago
6 0
<h2>Answer:</h2>

0.17M. Option B is correct

<h2>Explanations:</h2>

The formula calculating the molarity of a solution is given as:

M=\frac{n}{v}

where:

n is the moles of sodium chloride

v is the volume of the solution

Given the following parameters;

The volume of the solution = 3.0L

Determine the moles of NaCl

\begin{gathered} \text{Moles of NaCl=}\frac{Mass}{Molar\text{ mass}} \\ \text{Moles of NaCl=}\frac{29.2g}{23+35} \\ \text{Moles of NaCl=}\frac{29.2g}{58.5} \\ \text{Moles of NaCl=}0.499\text{moles} \end{gathered}

Calculate the required molarity

\begin{gathered} \text{Molarity}=\frac{0.499\text{moles}}{3.0L} \\ Molarity\approx0.17M \end{gathered}

Hence the molarity of the solution is 0.17M

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Answer:The correct names for the structure are:

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--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

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--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

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--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.

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