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3 years ago

3.74 ml of carbon dioxide (CO2) accidentally escaped during the experiment, what volume in liters would that be?

Chemistry

2 answers:

OLga [1]3 years ago

8 0

It would be at least 2.5 liters

BigorU [14]3 years ago

6 0

It is 0.00374 liters.

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Scoring Scheme: 3-3-2-1 Given the starting solution had a concentration of 1.25 M, how many moles of Co[H2O]6Cl2 were available

Pepsi [2]

Answer:

The solution has 0.00994 moles of Co[H2O]6Cl2

Explanation:

Complete question: Given the starting solution had a concentration of 1.25 M, how many moles of Co[H2O]6Cl2 were available in the amount of starting solution you used?

mL= 7.95

Step 1: Data given

Concentration of the starting solution = 1.25 M

Starting solution = Co[H2O]6Cl2

Step 2: Calculate molar mass of Co[H2O]6Cl2

Atomic mass of Co = 58.93 g/mol

Atomic mass of H = 1.01 g/mol

Atomic mass of O = 16.00 g/mol

atomic mass of Cl = 35.45 g/mol

Molar mass of Co[H2O]6Cl2 =

1*58.93 + 12*1.01 + 6*16.00 + 2*35.45 = 237.95 g/mol

Step 3: Calculate number of moles

C = n/v

⇒with C = the Concentration of the starting solution = 1.25 M

⇒with n= the number of moles = to be determined

⇒with v = the volume = 7.95 mL = 0.00795 L

n = C * V

n = 1.25 M * 0.00795 L

n = 0.00994 moles

The solution has 0.00994 moles of Co[H2O]6Cl2

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2 years ago

217 mL of neon gas at 551 celsius is brought to standard temperature (0 celsius) while the pressure is held constant. What is th

pantera1 [17]

Answer: The new volume is 72 ml

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=217ml\\T_1=551^oC=(551+273)K=824K\\V_2=?\\T_2=0^0C=(0+273)K=273K$

Putting values in above equation, we get:

$\frac{217ml}{824K}=\frac{V_2}{273K}\\\\V_2=72ml$

Thus the new volume is 72 ml

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2 years ago

A sample of gas initially has a volume of 1.42 L at 293 K and 1.30 atm. What volume will the sample have if the pressure changes

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Answer:

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Explanation:

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$\huge \orange {\mathbb {Answer}}$

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3 years ago

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