All categories

3 years ago

3.74 ml of carbon dioxide (CO2) accidentally escaped during the experiment, what volume in liters would that be?

Chemistry

2 answers:

OLga [1]3 years ago

8 0

It would be at least 2.5 liters

BigorU [14]3 years ago

6 0

It is 0.00374 liters.

You might be interested in

Find the mistake<br> Cu(NO3)2(s) + CuO(s) → 2NO(g) + O3(g)

kvv77 [185]

there are 2 copper atoms on the left side of the arrow, but none on the other side. there are also 7 oxygen atoms on the left hand side, but only 5 on the right hand side of the arrow.

3 0

3 years ago

An increase in the surface area of reactants in a heterogeneous reaction will result in what?

marusya05 [52]

It will result in an increase in the rate of rxn

4 0

3 years ago

Calculate the number of O atoms in 0.150 g of CaSO4 · 2H2O.

natulia [17]

Answer:

There are 0.00523 moles of oxygen in 0.150 grams of calcium sulfate crystal.

Explanation:

Mass of calcium sulfate crystal = m = 0.150 g

Molar mass of calcium sulfate crystal = M = 172 g/mol

Moles of magnesium nitrate = n

$n=\frac{m}{M}$

$n=\frac{0.150 g}{172 g/mol}=0.0008721 mol$

1 mole of calcium sulfate crystal has 6 moles of oxygen atoms. Then 0.004446 moles calcium sulfate crystal will have :

$6\times 0.0008721 mol=0.0052326mol\approx 0.00523 mol$

There are 0.00523 moles of oxygen in 0.150 grams of calcium sulfate crystal.

8 0

3 years ago

In the system model, the direction of the<br> arrow tells you that

AlladinOne [14]

Answer: Answer b

Explanation:

4 0

2 years ago

Read 2 more answers

What is the molarity of a NaCl stock used to make 750 ml of a dilute 10 mM solution if 5 ml of the concentrated solution was use

ch4aika [34]

Explanation:

The given data is as follows.

$M_{1}$ = 10 mM = $10 \times 10^{-3}$ M

$V_{1}$ = 750 ml, $V_{2}$ = 5 ml

$M_{2}$ = ?

Therefore, calculate the molarity of given NaCl stock as follows.

$M_{1} \times V_{1} = M_{2} \times V_{2}$

$10 \times 10^{-3} \times 750 ml = M_{2} \times 5 ml$

$M_{2}$ = 1.5 M

Thus, we can conclude that molarity of given NaCl stock is 1.5 M.

7 0

3 years ago