The period of a simple pendulum is given by
where
L is the pendulum length
g is the acceleration of gravity
If we move the same pendulum from Earth to the Moon, its length L remains the same, while the acceleration of gravity g changes. So we can write the period of the pendulum on Earth as:
where
is the acceleration of gravity on Earth, while the period of the pendulum on the Moon is
where
is the acceleration of gravity on the Moon.
If we do the ratio of the two periods, we get
but the gravity acceleration on the Moon is 1/6 of the gravity acceleration on Earth, so we can write
and we can rewrite the previous ratio as
so the period of the pendulum on the Moon is
Answer:
the momentum of the child is 337.5 kg.m/s
Explanation:
Given;
velocity of the wagon, v = 1.5 m/s
the combined mass of the child and the wagon, m = 225 kg
The momentum of the child is calculated as;
P = mv
substitute the given values of mass and velocity to determine the momentum,
P = 225 x 1.5
P = 337.5 kg.m/s
Therefore, the momentum of the child is 337.5 kg.m/s
PV = 400 x 0.08 = 32 J
Hope this helps
A hummingbird can flutter it's wings about 80 times per second.
4,800 divided by 60=80
The weight of the load is (mass) x (gravity)
= (350 kg) x (9.8 m/s²)
= 3,430 newtons .
The force on the surface of the liquid is the weight of the piston and its load.
The pressure on the surface of the liquid is (force) / (area)
= (3,430 newtons) / (1 m²)
= 3,430 pascals
= 3.43 kPa
This doesn't include anything for the weight of the piston without its load,
but it's certainly the closest of the choices.