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amid [387]
3 years ago
6

I need help with this I attached a picture.​

Chemistry
1 answer:
Olin [163]3 years ago
4 0
I’ll continuously post the answers in the comments, here is the first one:

Na = Metal
CI = Non-Metal
NaCI bond type: Covalent

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From a 2.875 g sample containing only iron, sand, and salt, 0.660 g of iron and 1.161 g of sand were separated and recovered. Wh
Serjik [45]

Answer:

36.66%

Explanation:

Step 1: Given data

  • Mass of iron: 0.660 g
  • Mass of sand: 1.161 g
  • Mass of the sample: 2.875 g
  • Mass of salt: ?

Step 2: Calculate the mass of salt

The mass of the sample is equal to the sum of the masses of the components.

m(sample) = m(iron) + m(sand) + m(salt)

m(salt) = m(sample) - m(iron) - m(sand)

m(salt) = 2.875 g - 0.660 g - 1.161 g

m(salt) = 1.054 g

Step 3: Calculate the percent of salt in the sample

We will use the following expression.

%(salt) = m(salt) / m(sample) × 100%

%(salt) = 1.054 g / 2.875 g × 100% = 36.66%

7 0
3 years ago
The _____ is one of the way paces where North America and Pacific Plates meet.
Morgarella [4.7K]

Answer:

The ring of fire

Explanation:

The ring of fire is where they meet or at the fault lines

8 0
3 years ago
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Ok, I need help with this one!!!!!!!!!!!!!!!!!!!! plz and thank you
Kitty [74]

Answer:

D)

Explanation:

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3 years ago
Why ozone is important to organic chemistry​
Nikolay [14]

Answer:

Ozone is good in the stratosphere because it absorbs all of the most energetic ultraviolet radiation (UV-C), most of the UV-B radiation and some of the least energetic UV radiation (UV-A). Ozone is “bad” in the troposphere because it is harmful to breathe and is the primary component of smog in summer.

5 0
3 years ago
A 1.450 g sample of an unknown organic compound , X, is dissolved in 15.0 g of toluene
muminat

Answer:

Molecular weight of the compound = 372.13 g/mol

Explanation:

Depression in freezing point is related with molality of the solution as:

\Delta T_f = K_f \times m

Where,

\Delta T_f = Depression in freezing point

K_f = Molal depression constant

m = Molality

\Delta T_f = K_f \times m

1.33 = 5.12 \times m

m = 0.26

Molality = \frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}

Mass of solvent (toluene) = 15.0 g = 0.015 kg

0.26 = \frac{Mole\ of\ compound}{0.015}

Moles of compound = 0.015 × 0.26 = 0.00389 mol

Mol = \frac{Mass\ in\ g}{Molecular\ weight}

Mass of the compound = 1.450 g

Molecular\ weight = \frac{Mass\ in\ g}{Moles}

Molecular weight = \frac{1.450}{0.00389} = 372.13\ g/mol

4 0
3 years ago
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