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Sloan [31]
3 years ago
12

The rate of a certain reaction is given by the following rate law: rate Use this information to answer the question below. At a

certain concentration of H2 and NH3, the initial rate of reaction is 4.0 x 105 M / s. What would the initial rate of the reaction be if the concentration of H2 were doubled
Chemistry
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

Explanation:

N_2+3H_2\rightarrow 2NH_3

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Initial rate of the reaction = R = 4.0\times 10^5 M/s

R = k\times [N_2][H_2]^3

4.0\times 10^5 M/s=k\times [N_2][H_2]^3

The initial rate of the reaction when concentration of hydrogen gas is doubled : R'

[H_2]'=2[H_2]

R'=k\times [N_2][H_2]'^3=k\times [N_2][2H_2]^3

R'=8\times k\times [N_2][H_2]^3

R'=8\times R=8\times 4\times 10^5 M/s=3.2\times 10^6 M/s

Initial rate of the reaction when concentration of hydrogen gas is doubled will be 3.2\times 10^6 M/s.

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In calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the
BartSMP [9]

Answer: The given statement is TRUE.

Explanation:

An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.

Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.

For example for the given equilibrium reaction;

2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)

K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.

7 0
3 years ago
What happened to the sound as vibration of an object increase in strength​
svlad2 [7]

Answer:

A.The sound becomes louder.

And

C.The sound waves get further.

Explanation:

Louder the sound it will travel long.

5 0
2 years ago
37.9 grams of an unknown substance undergoes a temperature increase of
jenyasd209 [6]

Answer:

1.023 J / g °C

Explanation:

m = 37.9 grams

ΔT = 25.0*C

H = 969 J

c = ?

The equation relating these equation is;

H = mcΔT

making c subject of formulae;

c = H / mΔT

c = 969 J / (37.9 g * 25.0*C)

Upon solving;

c = 1.023 J / g °C

4 0
2 years ago
5)
Drupady [299]

What amount of heat absorbs 50 g of steel (ce = 0.115 cal / g. ° C) that

does its temperature vary by 25 ° C?

Answer:

143.75cal

Explanation:

Given parameters:

Mass of steel  = 50g

Specific heat capacity of the steel  = 0.115cal/g°C

Temperature  = 25°C

Unknown:

Amount of heat = ?

Solution:

The amount of heat to cause this temperature change is dependent on mass and specific heat capacity of the substance.

  Amount of heat  = m C (ΔT)

m is the mass

c is the specific heat capacity

ΔT is the temperature change

 Now insert the parameters and solve;

  Amount of heat  = 50 x 0.115 x 25

  Amount of heat  = 143.75cal

4 0
2 years ago
How many atoms are in 58.93 grams of cobalt (Co)?
Vadim26 [7]
If you have 58.93g of Co it means that you only have 1 mol (use a periodic table to find the answer, if you had more find it by proportion, it's easier). 
There's 6.022 x 10^23 atoms per mol so you have 6.022 x 10^23 atoms of Co.
(once again if you had more mol, you could find the answer by proportions).
7 0
3 years ago
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