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ryzh [129]
3 years ago
11

A solid motor has an average thrust of 67,000 N, a specific impulse of 285 sec, and a propellant mass fraction of 0.92. Calculat

e the total mass of the vehicle for a 42 sec burn time.
Physics
1 answer:
Nikitich [7]3 years ago
3 0

Answer:

total mass is 1095.096 kg

Explanation:

given data

thrust = 67000 N

impulse time t = 285 sec

mass fraction = 0.92

to find out

total mass of the vehicle

solution

we know here thrust formula that is

thrust = m × g × t

put here value and find m

m = 67000 / 9.8(285)

m = 23.988 kg/s

so here mass fraction is express as

mass fraction = m × time /  (m × time + mf)

put here time after 42 sec

0.92 = 23.988 × 42 /  (23.988 × 42 + mf)

(23.988 × 42 + mf) 0.92 = 23.988 × 42

mf = 87.60 kg

total mass = mf + m × time

put here value

total mass = 87.60 + 23.988 × 42

total mass is 1095.096 kg

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The Earth orbits the Sun with a period of 3.16 x 107 seconds (1 year!) at a distance of 1.5 x 1011 m. The mass of the Earth is 6
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Answer:

a) M = 2  10³⁰ kg ,  b)    T_{m} = 5.81 10⁷ s

Explanation:

a) For this exercise let's use Newton's second law where force is the law of universal gravitation and acceleration is centripetal

           G m M / R² = m a

            a = v² / R

             G M / R = V²

The orbit of the two planets is approximately circular, therefore the velocity module (speed) is constant

            v = d / t

The distance is the length of the circular orbit

           d = 2π R

          G M / R = 4π² R² / T²

          G M T² = 4π² R³

Let's write this equation for each planet

For the earth

The period is T = 3.16 10⁷ s and the radius of the orbit R = 1.5 10¹¹ m, let's calculate the mass of the sun

         M = 4π² R³ / G T²

         M = 4π² (1.5 10¹¹)³ / (6.67 10⁻¹¹ (3.16 10⁷)²)

         M = 133.24 10³³ / 66.60 10³

         M = 2  10³⁰ kg

b) For this part we write this equation for the two points

For the earth

         T_{E}² = (4π² / G M)  R_{E}³

For mars

          T_{m}² = (4π² / G M)  R_{m}³

Let's divide the two expressions

         T_{m}² /  T_{E}² =  R_{m}³ /  T_{E}³

They indicate that the orbit of Mars is  R_{m} = 1.5  R_{E}

        T_{m}² /  T_{E}² = (1.5  R_{E} /  R_{E})³

        T_{m}² =  T_{E}² 1.5³

        T_{m}² = (3.16 10⁷)²  1.5³

        T_{m} = √ (33.70 10¹⁴)

        T_{m} = 5.81 10⁷ s

5 0
4 years ago
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