Answer: Conductor
Explanation: Because they do
Complete Question
An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.
Answer:
The torque is
Explanation:
From the question we are told that
The mass of the steel ball is
The length of arm is
The mass of the arm is
Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as
=>
=>
Generally the magnitude of torque about the athlete shoulder is mathematically represented as
=>
=>
Answer D
In alkali earth metals reacrivity increases from top to bottom (opposite of b)
This is because as you go down, the electron shells increase by 1 shell. The farther away a shell is from the nucleus, the higher its tendency to react.
D is true because the more reactive an alkali metal is, the more vigorous the reaction will be with water.
The units used to measure specific heat capacity is Joules per kilogram per Kelvin.
<h3>What is specific heat capacity?</h3>
It is the amount of heat absorbed per kilogram of material when the temperature rises by 1 kelvin.
Specific heat capacity C is the Joules of energy in form of heat per kilogram per Kelvin temperature. The units represented by
C = ___ J/kg.K
Thus, the units used to measure specific heat capacity is Joules per kilogram per Kelvin.
Learn more about specific heat capacity.
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Answer:
a. Horizontal component v = 12 m/s
b. Magnitude of velocity v = 20.78 m / s
Explanation:
Vₓ = 12.0 m / s eastward
β = 30.0 °
So
a.
Vt = Vₐ - Vₓ
Vₐ = 0 i
Vt = 0i - 12.0 = - 12 m/s
b.
Vₙ = 12 / sin (30 °)
Vₙ = 24 m / s
Vₙ = 24 * con (30 °)
Vₙ = 20.78 m / s