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Rufina [12.5K]
3 years ago
13

What is the name of the type of basaltic crust that moves under less dense crust? A. oceanic B. igneous C. continental D. asthen

osphere
Physics
2 answers:
givi [52]3 years ago
7 0

Answer:

Oceanic

Explanation:

Oceanic type of basaltic crust moves under less dense crust. Oceanic crust density increases because of volcanic eruption that leads to formation of igneous rocks( when lava is cooled down to magma and it is further cooled to form igneous rocks) these rocks being heavier move downward under the less dense crust.

Simora [160]3 years ago
3 0
The answer is A - oceanic
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Answer:

b. 1.1 m

Explanation:

It is given that the total distance between the masses is equal to the length of the board, which is 3 m. Therefore,

s_{1} + s_{2} = 3\ m\\\\s_{2} = 3\ m - s_{1}\ --------- eqn(1)

where,

s₁ = distance of fulcrum from left mass

s₂ = distance of fulcrum from right mass

In order to achieve balance, the torque due to both masses must be equal:

T_{1} = T_{2}\\m_{1}s_{1} = m_{2}s_{2}\\(25\ kg)(s_{1}) = (15\ kg)(s_{2})\\\\\frac{15\ kg}{25\ kg}(s_{2}) = s_{1}\\\\using\ eqn(1):\\(0.6)(3\ m - s_{1}) = s_{1}\\1.8\ m = 1.6\ s_{1}\\s_{1} = \frac{1.8\ m}{1.6}

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Hence, the correct option is:

<u>b. 1.1 m</u>

4 0
2 years ago
An eagle carries a fish up 50 m into the sky using 90 N of force. How much work did the eagle do on the fish? (Work: W = Fd)
Leno4ka [110]
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A lacrosse ball that is thrown straight upwards reaches a maximum height of 4.5 m. At what initial velocity was it thrown? (note
shtirl [24]

Answer:

The initial velocity was 9.39 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

The ball is thrown straight upward with initial velocity u

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At the maximum height velocity v = 0

The acceleration of gravity is -9.8 m/s²

We need to find the initial velocity

The best rule to find the initial velocity is <em>v² = u² + 2ah</em>, where v is

the final velocity, u is the initial velocity, a is the acceleration of

gravity and h is the height

⇒ v = 0 , h = 4.5 m , a = -9.8 m/s²

⇒ 0 = u² + 2(-9.8)(4.5)

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Add 88.2 to both sides

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Take square root for both sides

⇒ u = 9.39 m/s

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5 0
3 years ago
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Answer:

in 1 second 3m, in 2 seconds 6m, in 3 seconds 9m.

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