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OLEGan [10]
3 years ago
10

What are the five characteristics of a mineral

Chemistry
1 answer:
bulgar [2K]3 years ago
7 0

Answer:Five Characteristics of a Mineral

Minerals Are Natural. You must find minerals in nature; substances concocted in laboratories don't qualify. ...

Minerals Are Inorganic. ...

Minerals Are Solids. ...

Definite Chemical Composition. ...

Crystalline Structure.

Explanation:

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How is the moderm periodic table arranged?
ankoles [38]

Answer:

Explanation:

the elements are arranged according to their atomic number - not their relative atomic mass . In the periodic table the elements are arranged into: rows, called periods , in order of increasing atomic number. vertical columns, called groups , where the elements have similar properties

8 0
3 years ago
11.9 g Cl2 is reacted with 10.7 g NaOH. How many moles of NaCl are produced?
melisa1 [442]

Answer:

1. 7.256g of NaCl

2. 47.33g of Cl2

Explanation:

2 moles of Na reacts to produce 2 moles of NaCl

8 moles of Na will still produce 8 moles of NaCl

Mass of NaCl = molar mass of Nacl/moles of Nacl

=58.5/8

=7.256g of NaCl

From the equation, 2 moles of Na reacts with 1 mole of Cl2

3/2 moles of Cl2 will react with 3 moles of Na

Mass of Cl2 = 71/1.5

=47.33g of Cl2

Explanation:

4 0
3 years ago
Convert the density of water, 1.00 g/mL to lb/ft3. Provide only the numerical value in your answer with the correct number of si
PtichkaEL [24]

Answer:

The density of water 1.00 g/ml=62.43 lbs/ft^3.

Explanation:

Density of water = 1.00 g/mL

1 lb = 453.592 g

1 g=\frac{1}{453.592} lbs

ft^3=28316.8 mL

1 mL=\frac{1}{28316.8} ft^3

Density of the water in lb/ft^3:

\frac{1.00 g}{1 mL}=\frac{1.00}{453.592 } lb\times \frac{28316.8 }{1 ft^3}

=62.43 lbs/ft^3

The density of water 1.00 g/ml=62.43 lbs/ft^3.

3 0
4 years ago
Which statement best describes the characteristics of white light?
netineya [11]

Answer:

i believe its B

6 0
3 years ago
Determine the concentration of H+ in each solution at 25∘C
puteri [66]

Answer:

1: [H+] = 0.01 M

2: [H+] = 0.0001 M

3: [H+] = 0.0001 M

Explanation:

Step 1: data given

pH = -log[H+]

pH = pOH = 14

Step 2:

1. A solution with pH = 2.0

pH = 2

-log[H+] = 2.0

[H+] = 10^-2

[H+] = 0.01 M

2. A solution with pH = 4.0

pH = 4

-log[H+] = 4.0

[H+] = 10^-4

[H+] = 0.0001 M

3. A solution with pOH = 10.0

pH = = 14 - 10 = 4

pH = 4

-log[H+] = 4.0

[H+] = 10^-4

[H+] = 0.0001 M

4 0
3 years ago
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