What are you trying to do here?
Solve the graph, or make it appear as something else?
First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0
sec (x) (2sec (x) -2) = 0
Then we're going to separate the two to find the zeros of each because anything time 0 is zero.
sec(x) = 0
2sec (x) - 2 = 0
Now, let's simplify the second one as the first one is already.
Add 2 to both sides:
2sec (x) = 2
Divide by 3 on both sides:
sec (x) = 1
I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
Answer:
Step-by-step explanation:
The area of a rectangle can be found with the formula 
, where 
is the length of the rectangle and 
is the width.
From the given problem statement, we know that 
and 
, so we can fill in those values in the formula anbd solve for to get the width:
Divide both sides by 
to isolate by itself:
Answer: 19 ≥ 3z + 1 ≥ - 5
Answer:
B) f(x) ≥ 3x + 4
g of x is less than or equal to negative one half times x minus 5
Step-by-step explanation:
hope it helps
