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3 years ago

15

The amount of rainfall in January in a certain city is normally distributed with a mean of 3.7 inches and a standard deviation o

f 0.5 find the value of Q1

1 answer:

White raven [17]3 years ago

6 0

Answer:

x = 3.4

Step-by-step explanation:

given,

mean = 3.7 inches

standard deviation = 0.5

we want find the value of Q₁ = ?

the value of x such that, P(X < x)= 0.25

= > $P(\dfrac{X - \mu }{\sigma } < \dfrac{X - 3.7 }{0.5})=0.25$

= > $P(Z$

=> $\dfrac{x - 3.7}{0.5}= Z_{0.25}$

=> $\dfrac{x - 3.7}{0.5}= -0.67$

=> x = -0.67 x 0.5 + 3.7

=> x = 3.365

=> x = 3.4

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A car travels 2 1/3 miles in 3 1/2 minutes at a constant speed. Write an equation to represent the car travels in miles and minu

Korvikt [17]

Answer:

d = 0.666t , where d is in miles and t is in minutes.

d = 39.94h, where d is in miles and h is in hours.

Step-by-step explanation:

A car travels $2\frac{1}{3} = 2.33$ miles in $3\frac{1}{2} = 3.5$ minutes at a constant speed.

Let the relation between the distance (d) traveled by car in miles after traveling t minutes is d = kt ......... (1)

Now, putting d = 2.33 miles and t = 3.5 minutes in the above equation we get,

2.33 = 3.5k

⇒ k = 0.666 (Approx.)

So, the equation (1) becomes d = 0.666t. (Answer)

Let us assume that the relation between the distance (D) traveled by car in miles after traveling h hours is d = Kh ............ (2)

Now, putting D = 2.33 miles and T = 3.5/60 = 0.058 hours in the above equation, we get

2.33 = 0.058K

⇒ K = 39.94

So, the equation (2) we get, d = 39.94h (Answer)

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Scientific notation is written in the form a*10^n. What must be true about the a value?

Rama09 [41]

Answer:

It has to be a single digit between 1 and 10

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Which transformation is not isometric?

kumpel [21]

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Meredith invested $5,500 into an account that earned 5% interest per year. When she cashed out the investment to use it as a dow

Andrej [43]

Answer: B. $7739.05=5500(1.05)^t$

Step-by-step explanation:

The formula to find the compound amount (compounded yearly):-

$A=P(1+r)^t$ , where P is the principal amount invested, is the rate of interest and t is time period.

As per given , we have

P=$5500 , r=5% = 0.05 and A = $7,739.05.

Substitute all the values in the formula , we get

$7739.05=5500(1+0.05)^t$

$7739.05=5500(1.05)^t$

Hence, the equation describes Meredith's investment based on t, the number of years she kept the account open : $7739.05=5500(1.05)^t$

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3 years ago

What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n

Yakvenalex [24]

Answer:

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

$-2x^{2} +y=-5$ ----> equation A

$y=-3x^{2} +5$ -----> equation B

solve by substitution

substitute equation B in equation A

$-2x^{2} +(-3x^{2} +5)=-5$

solve for x

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$x^{2}=2$

$x=\pm\sqrt{2}$

<em>Find the value of y</em>

$y=-3x^{2} +5$

For $x=\sqrt{2}$ ----> $y=-3(\sqrt{2})^{2} +5=-1$

For $x=-\sqrt{2}$ ----> $y=-3(-\sqrt{2})^{2} +5=-1$

therefore

The solutions are

$(\sqrt{2},-1),(-\sqrt{2},-1)$

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

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