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andrew11 [14]
3 years ago
15

Bauxite is an ore that contains the element aluminum. If you obtained 108 grams of aluminum from an ore sample that initially we

ighed 204 grams, what is the mass percent of aluminum in this bauxite ore
Chemistry
1 answer:
Stels [109]3 years ago
8 0

Answer:

53% aluminium is present.

Explanation:

Given data:

Mass of aluminium in bauxite = 108 g

Total mass of sample = 204 g

Percentage of aluminium = ?

Solution:

Formula:

Percentage = Mass of aluminium / total mass of sample× 100

Now we will put the values in formula:

Percentage = 108 g/204 × 100

Percentage = 0.53  × 100

Percentage = 53%

So in given 204 g of bauxite there is 53% aluminium is present.

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The answer will be 25.92 L for 17.0 c
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(5.0 m3) ( 7.5 mmHg) = (P)(4.0m3)
anzhelika [568]

It looks like we are solving for a pressure.  All that is required is some algebraic manipulation to find our pressure in mmHg.

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(5.0 m³)(7.5 mmHg) = (P)(4.0m³)

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Divide:

9.375 = P

P = 9.4 mmHg (remember sig figs)

<h3>Answer:</h3>

9.4 mmHg

7 0
3 years ago
How does temperature, pressure and surface area affect the dissolving process
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8 0
3 years ago
Read 2 more answers
Would it be C???...idk<br> HELP
givi [52]

Answer:

C.  Butanal , is the aldehyde

Explanation:

A . It is carboxylic acid : ---COOH group

B. It is Ester : ----COOR group , Here R = CH3

C. It is Aldehyde : -----CHO group

D. It is ketone : ----C=O group

See image :

8 0
3 years ago
In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)2(aq) 2 NaBr(aq) PbBr2(s) 2 NaNO3(aq)
lyudmila [28]

Answer : The mass of NaBr is, 295.323 grams

Solution :

First we have to calculate the moles of NaNO_3.

\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}=\frac{244g}{85g/mole}=2.87moles

Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

Pb(NO_3)_2(aq)+2NaBr(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)

From the balanced reaction we conclude that

As, 2 moles of NaNO_3 react with 2 moles of NaBr

So, 2.87 moles of NaNO_3 react with 2.87 moles of NaBr

Now we have to calculate the mass of NaBr.

\text{Mass of }NaBr=\text{Moles of }NaBr\times \text{Molar mass of }NaBr

\text{Mass of }NaBr=(2.87mole)\times (102.9g/mole)=295.323g

Therefore, the mass mass of NaBr is, 295.323 grams

7 0
3 years ago
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