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andrew11 [14]
3 years ago
15

Bauxite is an ore that contains the element aluminum. If you obtained 108 grams of aluminum from an ore sample that initially we

ighed 204 grams, what is the mass percent of aluminum in this bauxite ore
Chemistry
1 answer:
Stels [109]3 years ago
8 0

Answer:

53% aluminium is present.

Explanation:

Given data:

Mass of aluminium in bauxite = 108 g

Total mass of sample = 204 g

Percentage of aluminium = ?

Solution:

Formula:

Percentage = Mass of aluminium / total mass of sample× 100

Now we will put the values in formula:

Percentage = 108 g/204 × 100

Percentage = 0.53  × 100

Percentage = 53%

So in given 204 g of bauxite there is 53% aluminium is present.

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How many moles are in 3.45 g of Ba(CIO3)2 ?
topjm [15]
<h3>Answer:</h3>

0.0113 mol Ba(ClO₃)₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structures</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.45 g Ba(ClO₃)₂

<u>Step 2: Identify Conversions</u>

Molar Mass of Ba - 137.33 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(ClO₃)₂ - 137.33 + 2(35.45) + 6(16.00) = 304.33 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.45 \ g \ Ba(ClO_3)_2(\frac{1 \ mol \ Ba(ClO_3)_2}{304.33 \ g \ Ba(ClO_3)_2})
  2. Multiply/Divide:                \displaystyle 0.011336 \ mol \ Ba(ClO_3)_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.011336 mol Ba(ClO₃)₂ ≈ 0.0113 mol Ba(ClO₃)₂

8 0
3 years ago
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