Thats hard as hell just drop out of the class lol
Answer:
KE = 1/2 mv^2=0.5x 10 X 20^2= 800
Explanation
Answer:
2KClO3 》》2KCl +3O2
C+ O2》》CO2
number of C moles
Required O2 moles (According to the mole ratio )
Relevant to the first equation, find the moles the KClO3, which is used to produce that amount of O2 moles
Now you can find the mass of KClO3
I mentioned the useful steps which can guide you to get the answer.
Explanation:
It depends of the temperature and the pressure. If temperature and pressure are standard 1 mol forms 22.4 liter. So 33.6 liters form 33.6/22.4 = 1.5 mols.
Now calculate the molar mass of carbon dioxide: 12 g/mol + 2x16 g/mol = 44 g/mol
The mass of the 1.5 mols is 1.5mol * 44 g/mol = 66 g.