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gayaneshka [121]
2 years ago
13

Express each quantity in regular notation along with its appropriate unit. a. 3.60 × 1 0 5 s 3.60×10 5 s b. 5.4 × 1 0 − 5 g / c

m 3 5.4×10 −5 g/cm 3 c. 5.060 × 1 0 3 k m 5.060×10 3 km d. 8.9 × 1 0 10 H z 8.9×
Chemistry
1 answer:
Gala2k [10]2 years ago
6 0

The numbers in normal notation are as follows:

a. 360000 s

b. 0.000054  g/cm³

c. 5060 km

d. 8900000000 Hz

<h3>What is standard form?</h3>

Standard form is a notation in which numbers are written in such a way that the number is between 1 and 10  multiplied by powers of ten.

Standard form is also known as scientific notation.

The given in numbers are in standard form:

a. 3.60 × 10⁵ s

b. 5.4 × 10⁻⁵ g/cm³

c. 5.060 × 10³ km

d. 8.9 × 10¹⁰ Hz

The numbers in normal notation are as follows:

a. 3.60 × 10⁵ s = 360000 s

b. 5.4 × 10⁻⁵ g/cm³ = 0.000054  g/cm³

c. 5.060 × 10³ km = 5060 km

d. 8.9 × 10¹⁰ Hz = 8900000000 Hz

In conclusion, standard form is also know as scientific notation.

Learn more about standard form at: brainly.com/question/19682432

#SPJ1

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Which of the following would have the largest pKa?
garri49 [273]

Answer:

CH3CH2NH3+/CH3CH2NH2 would have the largest pKa

Explanation:

To answer this question we must know Kb of CH3CH2NH2 is 5.6x10⁻⁴, and for C6H5NH2 is 4.0x10⁻¹⁰. And the CH3CH2NH3+ and C6H5NH3+ are related with these substances because are their conjugate base. That means:

pKa of  CH3CH2NH3+ =  CH3CH2NH2;  C6H5NH3+ =  C6H5NH2

Also, Kw / Kb = Ka

Thus:

pKa of CH3CH2NH3+/CH3CH2NH2 is:

Kw / kb = Ka = 1.79x10⁻¹¹

-log Ka = pKa

pKa = 10.75

pKa of C6H5NH3+/ C6H5NH2 is:

Kw / kb = Ka = 2.5x10⁻⁵

-log Ka = pKa

pKa = 4.6

That means CH3CH2NH3+/CH3CH2NH2 would have the largest pKa

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Which atom would be expected to have a half-filled <br> 3d subshell?
lana66690 [7]

Answer:

Manganese: Mn

Explanation:

The elestron configuration would show this is 25 electrons

Atomic number : 25

this electron configuration ends in 3d^{5}

half of the d subshell which is 10

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What is the evaluation of 60.1 x -9.2?
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That's the evaluation

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Which change occurs when an atom in excited state returns to ground state? 1 energy is emitted 2energy is absorbed 3 the number
kozerog [31]
The answer is number 1 - energy is emitted


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In a certain city, electricity costs $0.15 per kW·h. What is the annual cost for electricity to power a lamp-post for 6.00 hours
Vanyuwa [196]

(a) Power of bulb is 100 W, converting this into kW.

1 W=\frac{1}{1000}kW

Thus,

100 W =\frac{100}{1000}kW=0.1 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.1 kW\times 2190 h=219 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 219 kW.h will be:

Cost=\$ (219\times 0.15)=\$ 32.85

Therefore, annual cost of incandescent light bulb is \$ 32.85

(b) Power of bulb is 25 W, converting this into kW.

1 W=\frac{1}{1000}kW

Thus,

100 W =\frac{25}{1000}kW=0.025 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.025 kW\times 2190 h=54.75 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 54.75 kW.h will be:

Cost=\$ (54.75\times 0.15)=\$ 8.21

Therefore, annual cost of fluorescent bulb is \$ 8.21.

7 0
3 years ago
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