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Salsk061 [2.6K]
3 years ago
12

By what factor would a person’s weight be increased if Earth had 10 times its present mass, but the same volume?

Physics
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

10 times

Explanation:

The weight of the person is defined as the product of mass of person and the acceleration due to gravity of that planet.

Let the gravity is g.

W = m x g     .... (1)

Now the value of g depends on the mass of earth when the radius of earth is constant.

g' = 10 g

So, W'  = m x g' = m x 10 g = 10 mg = 10 W     (from (1)

So, the weight of the person becomes 10 times.

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A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point
pogonyaev

Answer:

L = 1.545 m

Explanation:

Let the total length of the rod is L

now the torque must applied on the other end of the rod so that it will balance the torque due to weight of rock on other side of fulcrum

so we will have

mg \times d = F(L - d)

so we have

325\times 9.8 \times 0.266 = F(L - 0.266)

F = 663 N

848 = 663(L - 0.266)

L = 1.545 m

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3 years ago
Rod A and rod B are cylindrical rods made of the same metal. amd they differ only in size. Rod B has double the length and doubl
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Answer:

it would take rod B twice as much time

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it would take rod B twice as much time as it is twice as thick and twice as long. Due to this reason it would take the electric charge not only more time but even more voltage to travel through the rod

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3 years ago
A 4.00-kg model rocket is launched, expelling 64.0 g of burned fuel from its exhaust at a speed of 675 m/s. What is the velocity
olga_2 [115]

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The velocity of the rocket is 7.8 m/s

Explanation:

3 0
3 years ago
ASAP do all will give 25 per person pls will mark brainiest
neonofarm [45]

Answer:

1) true

2) false

3) false

4) true

5) true

6) true

7) true

8) false

9) true

10) false

i think these are correct if im wrong on a few im sorry. Hope this helps at least a bit. And if i do get some wrong you know just to pick the opposite answer.

4 0
3 years ago
Four point masses of 3.0 kg each are arranged in a square on masslessrods. The length of a side of the square is 0.50m. What is
Zigmanuir [339]

Answer:

Part a)

I = 1.5 kg m^2

Part b)

I = 0.75 kg m^2

Part c)

I = 1.5 kg m^2

Explanation:

Part a)

Moment of inertia of the system about an axis passing through B and C is given as

I = mL^2 + mL^2 + m(0) + m(0)

I = 2mL^2

I = 2(3 kg)(0.50^2)

I = 1.5 kg m^2

Part b)

Moment of inertia of the system about an axis passing through A and C is given as

I = m(0^2) + m(\frac{L}{\sqrt2})^2 + m(0) + m(\frac{L}{\sqrt2})^2

I = 2m\frac{L^2}{2}

I = (3 kg)(0.50^2)

I = 0.75 kg m^2

Part c)

Moment of inertia of the system about an axis passing through the center of the square and perpendicular to the plane of the square

I = m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2

I = 4m\frac{L^2}{2}

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I = 1.5 kg m^2

8 0
3 years ago
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