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Salsk061 [2.6K]
3 years ago
12

By what factor would a person’s weight be increased if Earth had 10 times its present mass, but the same volume?

Physics
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

10 times

Explanation:

The weight of the person is defined as the product of mass of person and the acceleration due to gravity of that planet.

Let the gravity is g.

W = m x g     .... (1)

Now the value of g depends on the mass of earth when the radius of earth is constant.

g' = 10 g

So, W'  = m x g' = m x 10 g = 10 mg = 10 W     (from (1)

So, the weight of the person becomes 10 times.

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Find the time it takes for each object to accelerate from 0m/s to 40 m/s when pushed with 100N of force
Ivan

Answer:

40s

Explanation:

Given:

F=100N

V=40m/s and 0

force=change in momenton

F=mv-mu

t=40(100-0)/100

t=40/1

t=40s

4 0
3 years ago
-4, 0, -2/3, 4.11111…, 2, π, √6 'which members of this set are irrartional?
krok68 [10]

An irrational number is a real number that cannot be written as a simple fraction.

4 = 4/1 = rational

0 = 0/1 = rational

-2/3 = rational

4.11111 = irrational

2 = 2/1 = rational

π = 3.141592... = irrational

√6= irrational

Answer:

4.1111, π , √6

3 0
1 year ago
What is the acceleration of a 349 kg object that moved with a force of 750 N?
zavuch27 [327]

Answer:

<h3>The answer is 2.15 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

where

f is the force

m is the mass

From the question we have

a =  \frac{750}{349}  \\  = 2.14899713...

We have the final answer as

<h3>2.15 m/s²</h3>

Hope this helps you

4 0
2 years ago
You throw a ball with a speed of 25.0 m/s at an angle of 40.0â—¦ above the horizontal directly toward a wall. The wall is 22.0 m
kirza4 [7]
The horizontal speed is going to be the cosine of the given speed, therefore, the horizontal speed is 19.15 m/s. To find the time, divide the 22 m distance by the velocity. This results in 1.131 seconds, which is in between C and D.
3 0
3 years ago
Read 2 more answers
We see a full moon by reflected sunlight. How much earlier did the light that enters our eye leave the sun? the earth-moon and e
Tju [1.3M]

The time taken by the light reflected from sun to reach on earth will be 8.4 minutes.

To find the answer, we need to know about the distance travelled by light.

<h3>How to find the time taken by the light reflected from sun to reach on earth?</h3>
  • So, in order to solve this problem, we must first know how far the moon is from Earth and how far the Sun is from the moon.
  • These distances are given as 3.8×10^5 km (Earth-Moon) and 1.5×10^8 km (Sun- Earth).
  • Since the Moon and Sun are on opposite sides of Earth during a full moon, the light's distance traveled equals,

         d=(1.5*10^8km)+2(3.8*10^5km)=1.51*10^8km=1.51*10^{11}m

  • As we know that light travels at a speed of 300,000 km per second. then, the time taken by the light reflected from sun to reach on earth will be,

                      t=\frac{1.51*10^{11}}{3*10^8}=503.33 s\\t=\frac{503.33}{60}=8.4min

Thus, the time it takes for the light from the Sun to reach Earth and be recognized as 8.4 minutes.

Learn more about distance here:

brainly.com/question/11495758

#SPJ4

6 0
1 year ago
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