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Rainbow [258]
3 years ago
11

Please help ASAP please

Physics
1 answer:
Alex_Xolod [135]3 years ago
6 0

Answer:

14

Explanation:

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A ball is kicked from the ground into the air at a velocity of 3 m/s at an angle 35° above the horizontal and hits the ground so
Dennis_Churaev [7]

Answer:2.45 m/s

Explanation:

Given

Launch velocity(u)=3 m/s

launch angle=35^{\circ}

as the vertical velocity first decreasing to zero and then increases to original value so its avg is zero .

v_{avg}=\frac{displacement}{time}

v_{avg}=\frac{Range}{time}

v_{avg}=\frac{u\cos \theta \times t}{t}

thus v_{avg}=\frac{3\cos 35\times t}{t}

v_{avg}=3\cos 35=2.45 m/s

8 0
3 years ago
If 478 watts of power are used in 14 seconds, how much work was done?
sergiy2304 [10]
" 478 watts " means 478 joules per second.

In 14 seconds, the total work or energy is (14 x 478) = <em>6,692 joules</em>
7 0
3 years ago
Which of the following pairs of charged particles will result in a repelling force acting between the particles?
Maslowich
A and C because if both particles are alike they repel kind of like a magnet 
when two magnets are both the same side they repel
6 0
3 years ago
Knowing the P is 1110 N, determine the tension in the rope if the frame is in equilibrium. Express your answer in kN to the near
ra1l [238]

Explanation:

It is given that the value of P is 1110 N. And, for pin connection we have only two connections which are A_{x} and A_{y}. Let T be the tension is rope.

So,  \sum F_{y} = 0 and A_{y} - 1110 = 0

              A_{y} = 1110 N

     \sum F_{x} = 0

And,    T - A_{x} = 0

                  T = A_{x}

Also, \sum M_{A} = 0

                1110(0.75 + 0.75 + 0.75) - T(0.5 + 0.1) = 0

                    2497.5 - 0.6T = 0

                         T = 4162.5 N

                             = 4.16 kN

Therefore, we can conclude that the tension in the rope if the frame is in equilibrium is 4.16 kN.

3 0
3 years ago
A stone is thrown straight up in the air. If g represents the acceleration due to
maw [93]

Answer:

The correct false statement is;

As the stone rises, its potential energy decreases

Explanation:

When the stone is thrown straight up into the air, the initial velocity, u, progressively decreases according to the following equation;

v = u - g·t

Where;

v = The final velocity

g = The acceleration due to gravity = 9.81 m/s²

t = The time taken

Therefore whereby, the kinetic energy. K.E. is given by the equation , K.E. = 1/2 × m × u², as u reduces, the kinetic energy reduces

However, the potential energy, P.E. is given as P.E. = m × g × h

Where;

h = Height

m = The mass of the stone

Therefore, as the stone rises, the potential energy increases.

7 0
3 years ago
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