The indicated data are of clear understanding for the development of Airy's theory. In optics this phenomenon is described as an optical phenomenon in which The Light, due to its undulatory nature, tends to diffract when it passes through a circular opening.
The formula used for the radius of the Airy disk is given by,
![y_r=1.22\frac{\lambda f}{d}](https://tex.z-dn.net/?f=y_r%3D1.22%5Cfrac%7B%5Clambda%20f%7D%7Bd%7D)
Where,
Range of the radius
wavelength
f= focal length
Our values are given by,
State 1:
![d=2.00mm = 2*10^{-3}m](https://tex.z-dn.net/?f=d%3D2.00mm%20%3D%202%2A10%5E%7B-3%7Dm)
![f= 25mm = 25*10^{-3}m](https://tex.z-dn.net/?f=f%3D%2025mm%20%3D%2025%2A10%5E%7B-3%7Dm)
![\lambda = 750nm = 750*10^{-9}m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20750nm%20%3D%20750%2A10%5E%7B-9%7Dm)
State 2:
![d=8.00mm = 8*10^{-3}m](https://tex.z-dn.net/?f=d%3D8.00mm%20%3D%208%2A10%5E%7B-3%7Dm)
![f= 25mm = 25*10^{-3}m](https://tex.z-dn.net/?f=f%3D%2025mm%20%3D%2025%2A10%5E%7B-3%7Dm)
![\lambda = 390nm = 390*10^{-9}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20390nm%20%3D%20390%2A10%5E%7B-9%7D)
Replacing in the first equation we have:
![y_{r1} = 1.22\frac{(750*10^{-9})(25*10^{-3})}{2*10^{-3}}](https://tex.z-dn.net/?f=y_%7Br1%7D%20%3D%201.22%5Cfrac%7B%28750%2A10%5E%7B-9%7D%29%2825%2A10%5E%7B-3%7D%29%7D%7B2%2A10%5E%7B-3%7D%7D)
![y_{r1}= 11.4\mu m](https://tex.z-dn.net/?f=y_%7Br1%7D%3D%2011.4%5Cmu%20m)
And also for,
![y_{r2} =1.22\frac{(390*10^{-9})(25*10^{-3})}{8*10^{-3}}](https://tex.z-dn.net/?f=y_%7Br2%7D%20%3D1.22%5Cfrac%7B%28390%2A10%5E%7B-9%7D%29%2825%2A10%5E%7B-3%7D%29%7D%7B8%2A10%5E%7B-3%7D%7D)
![y_{r2} = 1.49\mu m](https://tex.z-dn.net/?f=y_%7Br2%7D%20%3D%201.49%5Cmu%20m)
Therefor, the airy disk radius ranges from
to ![11.4\mu m](https://tex.z-dn.net/?f=11.4%5Cmu%20m)
A. Angular momentum is always conserved would be the correct answer.
This is because like linear momentum (mvmv), angular momentum (r×mvr×mv) is a conserved quantity, where rr is the vector from the center of rotation. For a skater holding a static pose, for each particle making up her body, the contribution in magnitude to the total angular momentum is given by mirivimirivi. Thus bringing in her arms reduces riri for those particles. In order to conserve angular momentum, there is then an increase in the angular velocity.
hope this helps!
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Answer:
Explanation: The two main types of nuclear power are nuclear fusion and fission. Nuclear fission is used in nuclear power plants to create elements. Nuclear fission works by having a stray neutron collide with a nucleus. When this happens, it breaks the nucleus up, and another nuclei collides with another nucleus. A chain reaction occurs as this process continues. I personally think this type of nuclear power is dangerous because the result is radioactive byproducts. Also, meltdowns can occur in a nuclear power plant as a result of nuclear fission. I think nuclear fusion would be a much safer energy source. It is cheap and practically unlimited. Nuclear fusion occurs when two nuclei fuse together to create a larger nucleus. Nuclear fusion also proves Albert Einstein's equation E=mc2. The element you start out with is greater than the element you end up with after fusion occurs. This is due to some of the matter actually being converted into energy, which agrees with Einstein's equation. I think nuclear fusion is a safer energy source because it does not create radioactive byproducts that can be potentially harmful. Nuclear fusion, however, is not understood that well by scientists. As a result, we continue to use nuclear fission because we know how to use it. Until scientists fully understand nuclear fusion, scientists will continue to use nuclear fission for energy sources.
Answer:
the force of attraction between the two charges is 3.55 N.
Explanation:
Given;
first charge carried by the object, q₁ = 15.5 µC
second charge carried by the q₂ = -7.25 µC
distance between the two charges, r = 0.525 m
The force of attraction between the two charges is calculated as;
![F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(15\times 10^{-6})(7.25\times 10^{-6})}{(0.525)^2} \\\\F = 3.55 \ N](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bkq_1q_2%7D%7Br%5E2%7D%20%5C%5C%5C%5CF%20%3D%20%5Cfrac%7B%289%5Ctimes%2010%5E9%29%2815%5Ctimes%2010%5E%7B-6%7D%29%287.25%5Ctimes%2010%5E%7B-6%7D%29%7D%7B%280.525%29%5E2%7D%20%5C%5C%5C%5CF%20%3D%203.55%20%5C%20N)
Therefore, the force of attraction between the two charges is 3.55 N.