Answer:
Force exerted by the lighter block on the heavier block is 6.63 N
Explanation:
Given Data
F = 80N
m = 1kg
M = 11kg
Solution:
*We assume that there is no friction
Calculating the acceleration of the system
a =
a =
a =
a = 6.67m
Let's write the Equation of Motion of the heavier block
= F -
Ma = F -
force exerted by the lighter block on the heavier block is calculated as
= F - Ma
= 80 - (11 x 6.67)
= 6.63 N
Answer:
a) 2.5 m/s²
b) 6.12 m/s
Explanation:
Tension of rope = T = 356N
Weight of material = W = 478 N
Distance from the ground = s = 7.5 m
Acceleration due to gravity = g = 9.81 m/s²
Mass of material = m = 478/9.81 = 48.72
Final velocity before the bundle hits the ground = v
Initial velocity = u = 0
Acceleration experienced by the material when being lowered = a
a) W-T = ma
⇒478-356 = 48.72×a
⇒a = 2.5 m/s²
∴ Acceleration achieved by the material is 2.5 m/s²
b) v²-u² = 2as
⇒v²-0 = 2×2.5×7.5
⇒v² = 37.5
⇒v = 6.12 m/s
∴ Velocity of the material before hitting the ground is 6.12 m/s
Answer:
The height of the water slide is 0.878 m
Explanation:
Given that,
Distance = 2.52 m
Suppose Children slide down a friction less water slide that ends at a height of 1.80 m above the pool.
We need to calculate the time
Using equation of motion
Put the value in the equation
We need to calculate the velocity
Using formula of velocity
Put the value into the formula
We need to calculate height
Using conservation of energy
Put the value into the formula
Hence, The height of the water slide is 0.878 m.