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Masja [62]
3 years ago
13

In the case of mechanical waves, what causes or determines the speed of the waves, the frequency of the waves, and the wavelengt

hs of the waves?
Physics
2 answers:
lilavasa [31]3 years ago
6 0

Answer:

The medium determines the speed of the wave, the wavelength and frequency.

Explanation:For different media the speed of the wave will variate, because each media have different properties. The following equation makes a relation between the speed of the wave, the wavelength and the frequency:

v = \lambda.\nu (1)

Where v is the speed of the wave, \lambda is the wavelength and \nu is the frequency

Equation 1 shows that the speed of the wave is directly proportional to the product of the wavelength and the frequency. If the speed is lower the wavelength will decrease but the frequency increase, as is shown in equation 2:

\lambda = \frac{v}{\nu}   (2)

Equation 1 can be rewritten for the case of the frequency:

\nu = \frac{v}{\lambda}     (3)

So, according with equation 3, if the speed is higher the frequency will increase but the wavelength will decrease (inversely proportional).

Levart [38]3 years ago
3 0
The rate in witch ditermans the speed or vibration of the movment under the waves witch couses vibrational freequencys to be disrupted.
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Answer:

The magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J

Explanation:

Given;

radius of the circular loop of wire = 0.5 m

current in circular loop of wire = 2 A

strength of magnetic field in the wire = 0.3 T

τ = μ x Bsinθ

where;

τ is the magnitude of the magnetic torque

μ is the dipole moment of the magnetic field

θ is the inclination angle, for a plane area perpendicular to the magnetic field, θ = 90

μ = IA

where;

I is current in circular loop of wire

A is area of the circular loop = πr² = π(0.5)² = 0.7855 m²

μ = 2 x 0.7885 = 1.571 A.m²

τ = μ x Bsinθ =  1.571 x 0.3 sin(90)

τ = 0.4713 J

Therefore, the magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J

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1. An excited lithium atom emits a red light with wavelength a = 671nm. What is the corresponding photon energy? hc (6.63 x 10-3
Rudiy27

Answer:

 E = 2,964 10⁻¹⁹ J

Explanation:

The energy of the photons is given by the Planck relation

          E = h f

the speed of light is related to wavelength and frequency

          c = λ f

we substitute

          E = h c /λ

let's reduce the magnitude to the SI system

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let's calculate

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