Answer:
The magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J
Explanation:
Given;
radius of the circular loop of wire = 0.5 m
current in circular loop of wire = 2 A
strength of magnetic field in the wire = 0.3 T
τ = μ x Bsinθ
where;
τ is the magnitude of the magnetic torque
μ is the dipole moment of the magnetic field
θ is the inclination angle, for a plane area perpendicular to the magnetic field, θ = 90
μ = IA
where;
I is current in circular loop of wire
A is area of the circular loop = πr² = π(0.5)² = 0.7855 m²
μ = 2 x 0.7885 = 1.571 A.m²
τ = μ x Bsinθ = 1.571 x 0.3 sin(90)
τ = 0.4713 J
Therefore, the magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J
<span>Howard Gardner's Multiple Intelligences Theory, and VAK Visual Auditory Kinesthetic ... theory, so you will see references to more than the seven intelligences nowadays. ... If you think about the items aboveit's easy to see why Gardner and his .... and (to my knowledge) has not generated any complaint orcriticism about its ...</span><span>
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When rubbing two insulators together, electrons from one insulator will be transfered to the other. so the insulator that has just received electrons now has a negative charge as it has received more electrons (making it more negative) the insulator that has just lost electrons has just become positively charged. NEVER SAY THAT PROTONS HAVE BEEN TRANSEFERD.... EVER. ONLY ELECTORNS ARE TRANSFERED.
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Answer:
E = 2,964 10⁻¹⁹ J
Explanation:
The energy of the photons is given by the Planck relation
E = h f
the speed of light is related to wavelength and frequency
c = λ f
we substitute
E = h c /λ
let's reduce the magnitude to the SI system
λ = 671 nm = 671 10⁻⁹ m
let's calculate
E = 6.63 10⁻³⁴ 3 10⁸ /671 10⁻⁹
E = 2,964 10⁻¹⁹ J