In the case of mechanical waves, what causes or determines the speed of the waves, the frequency of the waves, and the wavelengt
2 answers:
Answer:
The medium determines the speed of the wave, the wavelength and frequency.
Explanation:For different media the speed of the wave will variate, because each media have different properties. The following equation makes a relation between the speed of the wave, the wavelength and the frequency:
(1)
Where v is the speed of the wave, \lambda is the wavelength and \nu is the frequency
Equation 1 shows that the speed of the wave is directly proportional to the product of the wavelength and the frequency. If the speed is lower the wavelength will decrease but the frequency increase, as is shown in equation 2:
(2)
Equation 1 can be rewritten for the case of the frequency:
(3)
So, according with equation 3, if the speed is higher the frequency will increase but the wavelength will decrease (inversely proportional).
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According to the law of conservation of momentum:
m1 = mass of first object
m2 = mass of second object
v1 = Velocity of the first object before the collision
v2 = Velocity of the second object before the collision
v'1 = Velocity of the first object after the collision
v'2 = Velocity of the second object after the collision
Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know.
m1 = 125 kg v1 = 12m/s v'1 = -12.5m/s
m2 = 235kg v2 = -13m/s v'2 = ?
Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation.
The velocity of the 2nd car after the collision is 0.03m/s.
m1 = mass of first object
m2 = mass of second object
v1 = Velocity of the first object before the collision
v2 = Velocity of the second object before the collision
v'1 = Velocity of the first object after the collision
v'2 = Velocity of the second object after the collision
Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know.
m1 = 125 kg v1 = 12m/s v'1 = -12.5m/s
m2 = 235kg v2 = -13m/s v'2 = ?
Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation.
The velocity of the 2nd car after the collision is 0.03m/s.
Answer:
2 seconds
Explanation:
The frequency of a wave is related to its wavelength and speed by the equation
where
f is the frequency
v is the speed of the wave
is the wavelength
For the wave in this problem,
v = 2 m/s
So the frequency is
The period of a wave is equal to the reciprocal of the frequency, so for this wave:
This means that the wave takes 4 seconds to complete one full cycle.
Therefore, the time taken for the wave to go from a point with displacement +A to a point with displacement -A is half the period, therefore for this wave:
Answer:
Part a)
Part b)
Part c)
d = 0.072 m
Explanation:
Part a)
As we know that the radius of the charge particle in constant magnetic field is given by
now for single ionized we have
Part b)
Similarly for doubly ionized ion we will have the same equation
Part c)
The distance between the two particles are half of the loop will be given as