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Slav-nsk [51]
3 years ago
5

Steve and José drove José's car to the beach during spring break. The 495 kilometer drive took them 8 hours and 30 minutes. What

was their average velocity for the trip?
Physics
1 answer:
Setler [38]3 years ago
7 0

Answer: The average velocity was 58 KPH

Explanation:

495/8.5 = 58.23 (average so only 58)

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Are we really real or are we all an allusion?Do you believe in past lives?How do you think you died in past life?
OLEGan [10]

Answer:

I don't even know

Explanation:

Shower thoughts

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3 years ago
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The stopping distances associated with slower speeds approximate the forward visibilities provided by low beam lights. However,
aleksandr82 [10.1K]

Answer:

a. True

Explanation:

Illumination distance is the distance, up to which the light of the vehicle can reach. Hence, it is a maximum distance from the, that driver can see.

Stopping distance is the minimum distance required by the car to stop after brakes are applied.

So, in order to avoid any accident the illumination distance must be greater than the stopping distance. So, the driver can stop the vehicle in time, when he sees something in front of it.

Since, the stopping distance in this case is two or three times longer than illumination distance. Therefore, low beam light does not provide enough visibility in high speed driving situations.

Hence, the correct option is:

<u>a. True</u>

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5 0
3 years ago
A car cruises at a constant rate of 50 miles per hour. How much time will it take to go 600 miles?
Len [333]
Speed is constant. 50 miles = 1 hour. 600/50 = 12. 1hr(12) = 12 hours.
7 0
3 years ago
What is an electric motor? Explain its operation.
tatyana61 [14]
An electric motor is an electrical machine that converts electrical energy into mechanical energy.

Electric motors work on the principal of the interaction between magnetic field electr-magnetism. A loop which is carrying the current is placed in a magnetic field. The loop will experience a torque. The torque starts rotating the coil and the propellers start to rotate when the current passes through the loop.
7 0
4 years ago
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An electron and a proton are held on an x axis, with the electron at x = + 1.000 m and the proton at x = - 1.000 m. Part A How m
r-ruslan [8.4K]

PART A)

Electrostatic potential at the position of origin is given by

V = \frac{kq_1}{r_1} + \frac{kq_2}{r_2}

here we have

q_1 = 1.6 \times 10^{-19} C

q_2 = -1.6 \times 10^{-19} C

r_1 = r_2 = 1 m

now we have

V = \frac{Ke}{r} - \frac{Ke}{r}

V = 0

Now work done to move another charge from infinite to origin is given by

W = q(V_f - V_i)

here we will have

W = e(0 - 0) = 0

so there is no work required to move an electron from infinite to origin

PART B)

Initial potential energy of electron

U = \frac{Kq_1e}{r_1} + \frac{kq_2e}{r_2}

U = \frac{9\times 10^9(-1.6\times 10^{-19}(-1.6 \times 10^{-19})}{19} + \frac{9\times 10^9(1.6\times 10^{-19}(-1.6 \times 10^{-19})}{21}

U = (2.3\times 10^{-28})(\frac{1}{19} - \frac{1}{21})

U = 1.15\times 10^{-30}

Now we know

KE = \frac{1}{2}mv^2

KE = \frac{1}{2}(9.1\times 10^{-31}(100)^2

KE = 4.55 \times 10^{-27} kg

now by energy conservation we will have

So here initial total energy is sufficient high to reach the origin

PART C)

It will reach the origin

4 0
3 years ago
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